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Illusion [34]
3 years ago
12

A motorcycle is moving at a speed of 21 m/s. The driver applies the brakes, giving hum an acceleration of -2.4 m/s^2. After 2 se

conds of braking, what is the speed of the motorcycle?
A. 25.8 m/s
B. 16.2 m/s
C. 4.8 m/s
D. 2.4 m/s
Physics
1 answer:
WARRIOR [948]3 years ago
6 0
<h3><u>Answer;</u></h3>

B. 16.2 m/s

<h3><u>Explanation</u>;</h3>

Using the equation;

v = u + at; where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken;

u = 21 m/s, a= -2.4 m/s^2 and t = 2 seconds

Therefore;

v = 21 + ((-2.4) × 2)

  = 21 - 4.8

 <u> = 16.2 m/s</u>

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Instrumento que se utiliza para medir fuerzas
Klio2033 [76]

Answer:

Un medidor de fuerza

A force gauge for all you English speakers

Explanation:

Un medidor de fuerza es un instrumento de medición que se utiliza para medir fuerzas.

A force gauge is a measuring instrument used to measure forces.

8 0
3 years ago
Car B has the same mass as Car A but is going twice as fast. If the same constant force brings both cars to a stop, how far will
evablogger [386]

Answer:four times

Explanation:

Given

mass of both cars A and B are same suppose m

but velocity of car B is same as of car A

Suppose velocity of car A is u

Velocity of car B is 2 u

A constant force is applied on both the cars such that they come to rest by travelling certain distance

using  to find the distance traveled

where, v=final velocity

u=initial velocity

a=acceleration(offered by force)

s=displacement

final velocity is zero

For car A

0-(u)^2=2\times a\times s

s_a=\frac{u^2}{2a}------1

For car B

0-(2u)^2=2\times a\times s_b

s_b=\frac{4u^2}{2a}----2

divide 1 and 2 we get

\frac{s_a}{s_b}=\frac{1}{4}

thus s_b=4\cdot s_a

distance traveled by car B is four time of car A

7 0
3 years ago
This problem is based on the whole idea of pressure but I’m having trouble on when the area circle formula is included.
Mice21 [21]

Answer:

6.23x10^6Pa

Explanation:

Data obtained from the question include:

F (force) = 490N

r (radius) = 0.005m

A (area of the circlular heel) =?

P (pressure) =.?

First, we'll begin by calculating the area of the circlular heel. This is illustrated below:

Area of circle = πr^2

Area = 22/7 x (0.00)^2

Area = 7.86x10^-5m^2

Pressure is simply force per unit area. It represented mathematically as

Pressure = Force /Area

Pressure = 490/7.86x10^-5

Pressure = 6.23x10^6N/m2

Recall: 1N/m2 = 1Pa

Therefore, 6.23x10^6N/m2 = 6.23x10^6Pa

Therefore, the woman exert a pressure of 6.23x10^6Pa on the floor

8 0
4 years ago
Gold in its pure form is too soft to be used for most jewelry. Therefore, the gold is mixed with other metals to produce an allo
Novay_Z [31]

Answer:

Explanation:18kt alloy contains

i) 75% of gold

rhogold=19.3g/cm^3

=75/100×19.3

=14.475g/cm^3

ii) 16% of silver

rhosilver=10.5g/cm^3

=16/100×10.5

=1.68g/cm^3

iii) 9% of copper

rhocopper =8.90g/cm^3

=9/100×8.9

=0.801g/cm^3

Overall density of 18kt gold

=(0.801+1.68+14.475)g/cm^3

=16.956g/cm^3

=17g/cm^3 to 3s.f

6 0
3 years ago
Hey pls help thanks a lot
galben [10]

Answer:

I am not sure about the answer as I don't have a proper calculator besides me now

Explanation:

but I used this equation:

(8.20)sin30(1-d)=10d

Idk whether it is correct or not, I'm just a student too

what is your method of doing this question?

4 0
3 years ago
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