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Katen [24]
3 years ago
13

What does a mutual fund do?

Physics
2 answers:
svp [43]3 years ago
8 0
Id say Its A as well, i recently just finished Econ class
Katyanochek1 [597]3 years ago
6 0

Answer: Option (A) is the correct answer.

Explanation:

An investment for collection of money by a company or bank from various investors.

Money from the investors is invested by a company or bank in share markets, bonds, market stock etc.

Basically mutual funds is an investment from which we can benefit if we invest for a longer period of time.

Therefore, we can conclude that a mutual fund invests the savings of many investors.

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How can you tell whether something has kinetic energy?
Bond [772]
<h2>If the object is moving then it has kinetic energy</h2>
6 0
3 years ago
A horse is grazing for food. It trots rightward 15 m to eat a carrot, then walks rightward 20 m, to another carrot, then turns l
mafiozo [28]

Answer:

<h3>0.42s</h3>

Explanation:

Velocity = Displacement/time

Displacement of the horse is the distance covered in a specified direction

Total distance of the horse towards the right = 15m + 20m = 35m

Total distance of the horse towards the left = 4m

Displacement = Distance towards the right - Distance towards the left

Displacement = 35m-4m

Displacement =  31m

Time taken = 74seconds

substitute the values gotten into the velocity formula

average velocity = 31m/74s

average velocity = 0.42m/s

Hence the magnitude of its average velocity is 0.42s

6 0
4 years ago
Which travels at a greater speed, visible or infrared light?
Ksju [112]
Infrared light because it is barely able to be seen
7 0
3 years ago
Using Kepler's 3rd Law of Planetary motion, determine the distance between the Earth and the center of the Moon.​
Ira Lisetskai [31]

Answer: the distance earth to moon is about 238,855 miles

Explanation:

8 0
3 years ago
A compressor receives air at 290 K, 100 kPa and a shaft work of 5.5 kW from a gasoline engine. It is to deliver a mass flow rate
Sladkaya [172]

Answer:

P_2=4091\ KPa

Explanation:

Given that

T₁ = 290 K

P₁ = 100 KPa

Power P =5.5 KW

mass flow rate

\dot{m}= 0.01\ kg/s

Lets take the exit temperature = T₂

We know that

P=\dot{m}\ C_p (T_2-T_1)

5.5=0.01\times 1.005(T_2-290})\\T_2=\dfrac{5.5}{0.01\times 1.005}+290\ K\\\\T_2=837.26\ K

If we assume that process inside the compressor is adiabatic then we can say that

\dfrac{T_2}{T_1}=\left(\dfrac{P_2}{P_1}\right)^{0.285}

\dfrac{837.26}{290}=\left(\dfrac{P_2}{100}\right)^{0.285}\\2.88=\left(\dfrac{P_2}{100}\right)^{0.285}\\

2.88^{\frac{1}{0.285}}=\dfrac{P_2}{100}

P_2=40.91\times 100 \ KPa

P_2=4091\ KPa

That is why the exit pressure will be 4091 KPa.

4 0
3 years ago
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