Suppose two cars depart from a four-way intersection at the same time, one heading north and the other heading west. The car hea
1 answer:
Answer:
Explanation:
The cars are moving away from the intersection at 90° from each other. The motion can be considered a right angled triangle with perpendicular and base being the speeds of the 2 cars. The hypotenuse is the linear distance between them. By Pytagoras theorem:
a) Distance= where a and b are the speeds of 2 cars.
Distance = =77.2t feet/second
b) Time = 2 hours 45 minutes; Convert this into seconds to get 9900 seconds. The distance formula will give distance in feet so we will divide it by 5280 to get miles
Distance= (77.2*9900)/5280 = 144.8 miles
c) 1 Miles = 5280 feet.
5280=77.2t;
Time=68.4 seconds;
The 2 cars are 1 miles apart after 68.4 seconds.
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Before the engines fail, the rocket's altitude at time <em>t</em> is given by
and its velocity is
The rocket then reaches an altitude of 1150 m at time <em>t</em> such that
Solve for <em>t</em> to find this time to be
At this time, the rocket attains a velocity of
When it's in freefall, the rocket's altitude is given by
where is the acceleration due to gravity, and its velocity is
(a) After the first 11.2 s of flight, the rocket is in the air for as long as it takes for to reach 0:
So the rocket is in motion for a total of 11.2 s + 32.6 s = 43.4 s.
(b) Recall that
where and
denote final and initial velocities, respecitively,
denotes acceleration, and
the difference in altitudes over some time interval. At its maximum height, the rocket has zero velocity. After the engines fail, the rocket will keep moving upward for a little while before it starts to fall to the ground, which means
will contain the information we need to find the maximum height.
Solve for and we find that the rocket reaches a maximum altitude of about 1930 m.
(c) In part (a), we found the time it takes for the rocket to hit the ground (relative to ) to be about 32.6 s. Plug this into
to find the velocity before it crashes:
That is, the rocket has a velocity of 196 m/s in the downward direction as it hits the ground.
Answer:
ΔV=0.484mV
Explanation:
The potential difference across the end of conductor that obeys Ohms law:
ΔV=IR
Where I is current
R is resistance
The resistance of a cylindrical conductor is related to its resistivity p,Length L and cross section area A
R=(pL)/A
Given data
Length L=3.87 cm =0.0387m
Diameter d=2.11 cm =0.0211 m
Current I=165 A
Resistivity of aluminum p=2.65×10⁻⁸ ohms
So
ΔV=IR
ΔV=0.484mV