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lesya [120]
3 years ago
15

Suppose two cars depart from a four-way intersection at the same time, one heading north and the other heading west. The car hea

ding north travels at the steady speed of 40 ft/sec and the car heading west travels at the steady speed of 66 ft/sec. (a) Find an expression for the distance between the two cars after t seconds. (Round your coefficients to one decimal place as needed.) 77.2t ft (b) Find the distance in miles between the two cars after 2 hours 45 minutes. (Round your answer to one decimal place.) 2 mi (c) When are the two cars 1 mile apart? (Round your answer to one decimal place.)
Physics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

Explanation:

The cars are moving away from the intersection at 90° from each other. The motion can be considered a right angled triangle with perpendicular and base being the speeds of the 2 cars. The hypotenuse is the linear distance between them. By Pytagoras theorem:

a) Distance=\sqrt{a^{2}t + b^{2}t  } where a and b are the speeds of 2 cars.

Distance = \sqrt{40^{2}t + 66^{2}t }=77.2t feet/second

b) Time = 2 hours 45 minutes; Convert this into seconds to get 9900 seconds. The distance formula will give distance in feet so we will divide it by 5280 to get miles

Distance= (77.2*9900)/5280 = 144.8 miles

c) 1 Miles = 5280 feet.

5280=77.2t;

Time=68.4 seconds;

The 2 cars are 1 miles apart after 68.4 seconds.

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The cycle used by the engine is composed of three processes: a process at constant pressure between point 1 and 2, a process at
aev [14]

Answer:

Isobaric process between points 1 and 2 while isochoric process between 2 and 3.

Explanation:

A themodynamic equilibrium system which changes from initial state to the final state by a process is known as thermodynamic processes. There are many different kinds of thermodynamic process which depends upon the thermodynamic quantities such as pressure, volume, temperature, entropy etc. The most common thermodynamic processes are isobaric, isothermal, isochoric and adiabatic.

When the temperature of the system remains same during the thermodynamic process, the process is known as isothermal.

When the heat of the system remains same during the thermodynamic process, the process is known as adiabatic.

When the volume of the system remains same during the thermodynamic process, the process is known as isochoric.

When the pressure of the system remains same during the thermodynamic process, the process is known as isobaric.

According to the question, between points 1 and 2 pressure remains constant, hence the process is isobaric.

According to the question, between points 2 and 3 volume remains constant, hence the process is isochoric.

5 0
3 years ago
Change into60f into c​
Reil [10]

Answer:

15.6 C

Explanation:

Here we are given a temperature in Fahrenheit (F). We want to convert it into Celsius degrees (C).

The conversion can be done by using the following equation:

T(C)=\frac{5}{9}(T(F)-32)

where

T(C) is the temperature in Celsius degrees

T(F) is the temperature in Fahrenheit degrees

In this problem, we have

T(F) = 60 F

Therefore, by applying the equation,

T(C)=\frac{5}{9}(60-32)=15.6 C

8 0
3 years ago
In science, Bob learns that the energy of a wave is directly proportional to the square of the waves amplitude. If the energy of
Naddika [18.5K]

Answer:

Probably none of the above. it's says directly proportional so there would be a proportionality constant.

4 0
4 years ago
20 points for an answer Explain how the distance of a planet from the sun affects the motion of the planet? Justify your respons
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The sun’s huge mass gives it a strong gravitational pull. Because of this gravitational pull, planets that are closer to the sun tend to have different motion than planets that are further away from the sun, because the gravity becomes stronger the closer you get. I hope this helped!
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4 years ago
Read 2 more answers
The person has an upward acceleration of 0.70 m/s^2 and is lifted from rest through a distance of 13 m. A rescue helicopter lift
Alex

Answer:

a)

840 N

b)

10920 J

c)

- 10192 J

d)

4.3 m/s

Explanation:

a)

T = tension force in the cable in upward direction = ?

a = acceleration of the person in upward direction = 0.70 m/s²

m = mass of the person being lifted = 80 kg

Force equation for the motion of person in upward direction is given as

T - mg = ma

T = m (g + a)

T = (80) (9.8 + 0.70)

T = 840 N

b)

d = distance traveled in upward direction = 13 m

W_{t} = Work done by tension force

Work done by tension force is given as

W_{t} = T d

W_{t} = (840) (13)

W_{t} = 10920 J

c)

d = distance traveled in upward direction = 13 m

W_{g} = Work done by person's weight

Work done by person's weight is given as

W_{g} = - mg d

W_{g} = - (80 x 9.8) (13)

W_{g} = - 10192 J

d)

F_{net} = Net force on the person = ma = 80 x 0.70 = 56 N

v₀ = initial speed of the person = 0 m/s

v = final speed

Using work-energy theorem

F_{net} d = (0.5) m (v² - v₀²)

(56) (13) = (0.5) (80) (v² - 0²)

v = 4.3 m/s

6 0
4 years ago
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