The final velocity is of the car is 35.
<u>Explanation:</u>
The car initially moves in the velocity 20 . It then accelerated by 3
for 5 seconds.
The formula to find final velocity,
: initial velocity of the car.
a: acceleration rate.
t: time.
: final velocity
From the given information,
= 20
.
a=3.
t= 5s.
=20+3(5).
=20+15.
=35.
∴The final velocity of the moving car is 35.
Given that,
The radius of a circular path, r = 32 m
The time of one revolution of a rider is 0.98 s.
To find,
The speed of the rider.
Solution,
Let v is the speed of the rider. Speed is equal to total distance divided by time taken.
So, the speed of the rider is 205.16 m/s.
Answer:
ground state
Explanation:
Lets take
n=3 ,n=2 ,n=1 are the energy level.
Energy level n=1 is the ground energy level.
The energy from 3 to 1 = hν
The energy from 3 to 2 = hν₁
The energy from 2 to 1 = hν₂
We can say that
hν = hν₁ + hν₂
If the electron were de-excitation from the third level to ground level then the sum of emitted frequency will be equal to the frequency of a single electron.
Therefore the answer is ground state.
