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2 years ago

Which atomic number is the threshold value below which fusion may occur?

Physics

2 answers:

Luda [366]2 years ago

7 0

Answer:

The atomic number 26(iron) is the threshold value below which the fusion might occur.

Explanation:

Nuclear fusion is a reaction in which two or more nuclei are combined to form one or more different atomic nuclei and subatomic particles.

Energy released in a fusion reaction is because of a key feature of nuclear matter called the binding energy which is a measure of the efficiency with which its constituent nucleons are bound together.

As we go up in atomic number, the energy released per nuclei goes down until it hits a minimum which is for atomic number 26 (iron) and fusion is not possible.

mash [69]2 years ago

7 0

Answer:

Atomic no. 26 i.e. Iron

Explanation:

Nuclear Fusion is a process in which two or more nucleus are fused(combined) together to make heavier nucleus and release a lot of energy and other subatomic particles in the process. Considerable amount of energy is required to fuse the nucleus together but the output energy is much more than the input energy. It becomes an exothermic process.

In case of heavier nuclei, this doesn't hold true as the process becomes endothermic. That means the output energy will be way lesser than the input energy given to fuse the nucleus. This happens for elements of atomic no. 26 or above. Even in stars we can find element till atomic no. 26 as they can be formed by fusion. When a star reaches to iron fusion stage that is the end of it and it explodes into a supernova.

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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150

Sever21 [200]

Answer: $2.89\approx 2.9^{\circ}C/s$

Explanation:

Given

$Power\left ( P\right )=150 MW$

mass of core $\left ( m\right )=1.60\times 10^5 kg$

Average specific heat $\left ( C\right )=0.3349 KJ/kg^{\circ}C$

And rate of increase of temperature = $\frac{\mathrm{d}T}{\mathrm{d} t}$

Now

P= $mc\frac{\mathrm{d}T}{\mathrm{d} t}$

$150\times 10^6=1.60\times 10^5\times 0.3349\times \frac{\mathrm{d}T}{\mathrm{d} t}$

Thus $\frac{\mathrm{d}T}{\mathrm{d} t}=[tex]\frac{1.60\times 10^5\times 0.3349}{150\times 10^6}$

$\frac{\mathrm{d}T}{\mathrm{d} t}=2.89\approx 2.9^{\circ}C/s$

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3 years ago

Why is it important to keep the muzzle of a firearm pointed in a safe direction, even though the firearm's safety is engaged?

Gnom [1K]

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kipiarov [429]

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lidiya [134]

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<h3>Additional information:-</h3>

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3 years ago

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