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Gekata [30.6K]
3 years ago
11

A very flammable substance would not be used in children’s clothing? true or false

Chemistry
1 answer:
Alex73 [517]3 years ago
7 0
True because certain fabric will catch on fire 
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Combustibilty defined?
Phantasy [73]
Capable of catching fire
8 0
2 years ago
Is material that has a density of 0.2g/ml good for building a bridge or for making couch cushions
lisov135 [29]
D = 0.2 g / ml = 0.2 g / cm³
For example, density of steel is 7.85 g / cm³.
Density of pure water is 1.0 g/cm³. An object which has a density < 1.0 g/cm³ will float in water.
Answer: Material that has a density of 0.2 g/ml ( 0.2 g/cm³ ) is good for making couch cushions. 
8 0
3 years ago
Read 2 more answers
An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then,
kolezko [41]

Answer:

Number of proton is 11

Number of neutrons is 12

Number of electrons is 10

Explanation:

For a neutral Na, Sodium atom:

The mass number P+N = 23

Atomic number(E or P) = 11

A charged Na atom that has lost an electron is positively charged and so:

Number of proton = 11 (Still the same)

Number of neutrons = 12

Number of electrons = 11-1=10 (the atom has lost an electron)

If an atom loses electron, it becomes positively charged ie P>E

7 0
3 years ago
Read 2 more answers
How many kilojoules of heat are released when 0.72 mole of oxygen gas are used to combust methane?
KonstantinChe [14]

0.72 mole of oxygen would produce 320.4 kJ of heat.

<u>Explanation:</u>

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (ℓ) + 890kJ

According to the equation,

2 moles of O₂ produces 890 kJ of heat

So, 0.72 moles of O₂ will produce:

= \frac{890}{2} X 0.72\\\\= 445 X 0.72\\\\= 320.4 kJ

Therefore, 0.72 mole of oxygen would produce 320.4 kJ of heat.

6 0
3 years ago
When copper is bombarded with high-energy electrons, X rays are emitted. Calculate the energy (in joules) associated with the ph
Scrat [10]

Answer:

E = 12.92 × 10^(-16) J

Explanation:

Formula for energy is;

E = hc/λ

Where;

h is Planck's constant = 6.63 x 10^(-34) J.s

c is speed of light = 3 × 10^(8) m/s

λ is wavelength = 0.154 nm = 0.154 × 10^(-9) m

E = (6.63 x 10^(-34) × 3 × 10^(8))/(0.154 × 10^(-9))

E = 12.92 × 10^(-16) J

6 0
3 years ago
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