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Effectus [21]
3 years ago
9

Which best compares freezing and condensation?

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
5 0
They both involve the release of heat
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A 50.0-g sample of liquid water at 25.0 °c is mixed with 23.0 g of water at 79.0 °c. the final temperature of the water is ___
I am Lyosha [343]

<span><span>m1</span>Δ<span>T1</span>+<span>m2</span>Δ<span>T2</span>=0</span>

<span><span>m1</span><span>(<span>Tf</span>l–l<span>T<span>∘1</span></span>)</span>+<span>m2</span><span>(<span>Tf</span>l–l<span>T<span>∘2</span></span>)</span>=0</span>

<span>50.0g×<span>(<span>Tf</span>l–l25.0 °C)</span>+23.0g×<span>(<span>Tf</span>l–l57.0 °C)</span>=0</span>

<span>50.0<span>Tf</span>−1250 °C+23.0<span>Tf</span> – 1311 °C=0</span>

<span>73.0<span>Tf</span>=2561 °C</span>

<span><span>Tf</span>=<span>2561 °C73.0</span>=<span>35.1 °C</span></span>

8 0
3 years ago
3: Consider molecules of hydrogen (tiny ones) and oxygen (bigger ones) in a gas mixture. If they have the same average kinetic e
mezya [45]

Answer: Hydrogen molecules will have greatest average speed.

Explanation:

The formula for average speed is  :

\mu_{av}={\sqrt{\frac{8RT}{\pi\times M}}}

R = gas constant  

T = temperature  

M = Molecular Mass

Now putting all the values:

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{8RT}{\pi\times M_{H_2}}}/{\sqrt{\frac{8RT}{\pi\times M_{O_2}}}

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{16}{2}}

\frac{\nu_{av}_{H_2}}{\nu_{av}_{O_2}}=8

Thus average speed of hydrogen is 8 times the average speed of oxygen. Thus hydrogen molecules will have greatest average speed

8 0
3 years ago
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
PLEASE HELP A HOMIIE
Allushta [10]

Answer:

Its the first one. The cells are arranged for structure.

Explanation:

Animal cells do not need to maintain a shape since out bodies do it for us. Plant cells need something for structure.

8 0
3 years ago
What is the Law of Definite Composition and how does it apply to pure substances and mixtures?
Lyrx [107]

Answer:

The Law of Definite Proportions ensures that chemical compounds are always created using the same proportions, regardless of the amount of the compound which is being made

5 0
3 years ago
Read 2 more answers
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