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sertanlavr [38]
4 years ago
7

Identify the type of friction acting in each scenario. A surfer rides an ocean wave. A bowling ball travels down a bowling lane.

A baseball flies through the air. A hose rests on the edge of a truck.
Chemistry
2 answers:
pishuonlain [190]4 years ago
7 0
1. fluid  2.rolling   3.air resistance   4.static


Anton [14]4 years ago
4 0

Explanation;

1. Fluid friction: Friction between the layers of fluid moving relative to each other.It is the force which resist the motion of fluid in itself or any other medium moving through fluid.

  • A surfer rides an ocean wave : Fluid friction
  • A baseball flies through the air: Fluid friction

2. Rolling friction is the force which the resists the motion of any rolling object.

  • A bowling ball travels down a bowling lane : Rolling friction

3. Static friction is the force which the keeps the object at rest.

  • A hose rests on the edge of a truck. : Static friction
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Answer:

The law of reflection states that the angle of incidence and the angle of reflection are always equal.

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You react 2.43 grams of magnesium with oxygen from the air according to the following reaction. The final mass of the product, m
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Answer:

The mass of oxygen that reacted is approximately 1.6 grams of oxygen

Explanation:

The given information are;

The mass of magnesium in the reaction = 2.43 grams

The final mass of the magnesium oxide = 4.12 grams

The chemical equation for the reaction is given as follows;

2Mg + O₂  →  2MgO

From which we see that two moles of magnesium, Mg, reacts with one mole of oxygen gas molecule, O₂, to produce two moles of magnesium oxide, MgO

The number of moles of magnesium present, n_{Mg}, is given as follows;

n_{Mg} = \dfrac{Mass \ of \, magnesium}{Molar \ mass \ of \, magnesium} = \dfrac{2.43}{24.305} \approx 0.1 \ moles

By the given chemical equation, 2 moles of magnesium reacts with one mole of O₂, therefore;

1 mole of magnesium will react with 1/2  moles of oxygen which is 0.5 moles of oxygen also;

0.1 mole of magnesium will react with 0.05 moles of oxygen

The mass of one mole of oxygen = The molar mass of oxygen = 32 g/mol

The mass of oxygen in the reaction = The number of moles of oxygen × The molar mass of oxygen

The mass of oxygen in the reaction = 0.05 × 32 = 1.6 grams

Also from the molar mass  of MgO which is 40.3044 g/mol, we have;

The mass fraction of oxygen = 16/40.3044 = 0.39698 ≈ 0.4

The mass of oxygen = 0.39698 × 4.12 = 1.636 g

Therefore, the mass of oxygen in the reaction is approximately 1.6 grams.

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Explanation:

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A solution contains 0.25 M Ni(NO3)2 and 0.25 M Cu(NO3)2. Can the metal ions be separated by slowly adding Na2CO3? Assume that fo
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Explanation:

Ksp of NiCO3 = 1.4 x 10^-7

Ksp of CuCO3 = 2.5 x 10^-10

Ionic equations:

NiCO3 --> Ni2+ + CO3^2-

CuCO3 --> Cu2+ + CO3^2-

[Cu2+][CO3^2-]/[Ni2+][CO3^2-]

= (2.5* 10^-10)/(1.4* 10^-7)

= 0.00179.

[Cu2+]/[Ni2+]

= 0.00179

= 0.00179*[Ni2+]

If all of Cu2+ is precipitated before Na2CO3 is added.

= 0.00179 * (0.25)

The amount of Cu2+ not precipitated = 0.000448 M

The percent of Cu2+ precipitated before the NiCO3 precipitates = concentration of Cu2+ unprecipitated/initial concentration of Cu2+ * 100

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Therefore, percentage precipitated = 100 - 0.18

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The surface of planet mercury and our moon contain some very large craters that are
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