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ruslelena [56]
3 years ago
15

In 1938, Otto Hahn and Fritz Strassman discovered that uranium nuclei could spit and form smaller nuclei, or different elements.

Chemistry
2 answers:
ehidna [41]3 years ago
8 0
Bbbbbbbbbbbbbbbbbbbbbbbbbbbb
trasher [3.6K]3 years ago
4 0

Answer: I believe it’s c

Explanation:

Because during fission the atom often splits into 2+

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Nonpolar compound would be symmetrical
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Read 2 more answers
Calculate the percent by mass of a solution of Ca(NO3)2 that has 22.63 g dissolved in 896.92 g of water.
never [62]

Hey there!

To calculate the percent by mass of the Ca(NO₃)₂ we need to find the total mass first by adding.

896.92 + 22.63 = 919.55

In total, the solution is 919.55 grams.

To find the percent of Ca(NO₃)₂ in the solution, divide the mass of Ca(NO₃)₂ by the total mass and multiply by 100.

22.63 ÷ 919.55 = 0.0246

0.0246 x 100 = 2.46

Ca(NO₃)₂ makes up 2.46% of the solution.

Hope this helps!

6 0
3 years ago
What is the relationship among solutions solutes and solvents
jenyasd209 [6]

Answer:

Solvents are substances in which solutes dissolves while solutes are substances that dissolve in solvents and solutions result from mixing solvents and solutes.

Explanation:

  • A solvent is a substance such as water that dissolves a solute.
  • A solute is a substance that dissolves in a solvent. For example, when sodium chloride dissolves in water, sodium chloride is the solute and water is the solvent.
  • A solution, on the other hand, results from combining a solute and a solvent. Therefore, a mixture of water and sodium chloride forms the solution.
6 0
3 years ago
A vessel of volume 100ml contains 10% of oxygen and 90% of an unknown gas. The gases diffuses in 86 second through a small hole
swat32

The molecular weight of unknown gas : 23.46 g/mol

<h3>Further explanation</h3>

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

\tt 0.1\times 32+0.9\times M=3.2+0.9M

Graham's Law :

\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol

7 0
3 years ago
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