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IceJOKER [234]
2 years ago
14

A 3kg plastic tank that has a volume of 0.2m ^3 Is filled with liquid water . Assuming the density of water is 1000kg/m^3 determ

ine the weight of the combined system
Physics
1 answer:
stepan [7]2 years ago
8 0

Answer:

The weight of the combined system is 1989.8 N.

Explanation:

The weight, W, of an object can be expressed as;

W = mg

where m is the mass of the object, and g is the acceleration due to gravity.

Weight of the combined system = weight of tank + weight of water

mass of the plastic tank = 3 kg

weight of the plastic tank = m x g

                               = 3 x 9.8

                               = 29.4 N

Weight of the plastic tank is 29.4 N

But,

density = \frac{mass}{volume}

mass = density x volume

volume of water = 0.2 m^{3}, density of water = 1000 kg/m^{3}.

mass  = 1000 x 0.2

         = 200

mass of water = 200 kg

weight of water = 200 x 9.8

                   = 1960 N

Thus,

combined weight of the system = 29.4 + 1960

                        = 1989.8 N

The weight of the combined system is 1989.8 N.

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What is the major difference between the natural frequency and the damped frequency of oscillation.​
natita [175]

Answer:

This causes the amplitude of the oscillation to decay over time. The damped oscillation frequency does not equal the natural frequency. Damping causes the frequency of the damped oscillation to be slightly less than the natural frequency

6 0
2 years ago
If you added 5 x more mass into a wheelbarrow, how much greater would
aev [14]

Answer:

5 x biger

Explanation:

becuze if it ia 5× more it nids 5×more force to be =

7 0
3 years ago
Calculate the required rate of return for Climax Inc., assuming that (1) investors expect a 4.0% rate of inflation in the future
Westkost [7]

Answer:

Required rate of return = 18.5 %

Explanation:

given,                            

rate of inflection = 4 %

risk free rate = 3 %                      

market risk premium = 5 %                    

firm has a beta  = 2.30                                  

rate of return has averaged 15.0% over the last 5 years

now,                                                                      

Nominal risk free rate = risk free rate  + inflation

                                    = 3%  +  4%

                                   = 7%

Required rate of return = Nominal risk free rate + β (RPM)

                                       = 7%       +          2.3 x 5.0%

Required rate of return = 18.5 %

5 0
3 years ago
A carpenter is driving a 15.0-g steel nail into a board. His 1.00-kg hammer is moving at 8.50 m/s when it strikes the nail. Half
bekas [8.4K]

Answer: The increase in temperature of the nail after the three blows is 8.0636 Kelvins. The correct option is (d).

Explanation:

Kinetic energy of the hammer ,K.E.=

\frac{1}{2}mv^2=\frac{1}{2}1.00 kg\times (8.50 m/s)^2=36.125 J

Half of the kinetic energy of the hammer is transformed into heat in the nail.

Energy transferred to the nail in one blow =

\frac{1}{2}K.E.=\frac{1}{2}\times 36.125 J=18.0625 J

Total energy transferred after 3 blows,Q =3\times 18.0625 J=54.1875 J

Mass of the nail = 15 g = 0.015 kg

Change in temperature =\Delta T

Specif heat of the steel = c = 448 J/kg K

Q=mc\Delta T

54.1875 J=0.015 kg\times 448 J/kg K\times \Delta T

\Delta T=8.0636 K\approx 8.1 K

The increase in temperature of the nail after the three blows is 8.1  Kelvins.Hence, correct option is (d).

4 0
3 years ago
A child’s toy that is made to shoot ping pong balls consists of a tube, a spring (k = 18 N/m) and a catch for the spring that ca
UkoKoshka [18]

Answer:

The height is 3.1m

Explanation:

Here we have a conservation of energy problem, we have a conversion form eslastic potencial  energy to gravitational potencial energy, so:

E_e=\frac{1}{2}K*x^2\\E_e=\frac{1}{2}18N/m*(9.5*10^{-2}m)^2\\E_e=0.081J

then we have only gravitational potencial energy when the ball is at its maximun height.

E_g=m*g*h

because all the energy was transformed Eg=Ee

h=\frac{0.081J}{9.8m/s^2*m}

searching the web, the mass of a ping pong ball is 2.7 gr in average. so:

h=\frac{0.081J}{9.8m/s^2*(2.7*10^{-3}kg)}\\h=3.1m

6 0
3 years ago
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