A 3kg plastic tank that has a volume of 0.2m ^3 Is filled with liquid water . Assuming the density of water is 1000kg/m^3 determ
1 answer:
Answer:
The weight of the combined system is 1989.8 N.
Explanation:
The weight, W, of an object can be expressed as;
W = mg
where m is the mass of the object, and g is the acceleration due to gravity.
Weight of the combined system = weight of tank + weight of water
mass of the plastic tank = 3 kg
weight of the plastic tank = m x g
= 3 x 9.8
= 29.4 N
Weight of the plastic tank is 29.4 N
But,
density =
mass = density x volume
volume of water = 0.2 , density of water = 1000 kg/
.
mass = 1000 x 0.2
= 200
mass of water = 200 kg
weight of water = 200 x 9.8
= 1960 N
Thus,
combined weight of the system = 29.4 + 1960
= 1989.8 N
The weight of the combined system is 1989.8 N.
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Gravitational potential energy can be calculated using the formula:
Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height
On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.
So put in what you know and solve for what you don't know.
m = 10kg
g = 3.7m/s^2
h = 1m
So we put that in and solve it.
Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height
On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.
So put in what you know and solve for what you don't know.
m = 10kg
g = 3.7m/s^2
h = 1m
So we put that in and solve it.
Answer:
Explanation:
We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.
<h3>1. Force of 1st Object </h3>First, we can find the force of the first, 8 kilogram object.
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.
- m= 8 kg
- a= 1.6 m/s²
Substitute these values into the formula.
Multiply.
Now, use the force we just calculated to complete the second part of the problem. We use the same formula:
This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.
- F= 12.8 kg *m/s²
- m= 2 kg
Substitute the values into the formula.
Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.
The units of kilograms cancel.
The acceleration is 6.4 meters per square second.