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IceJOKER [234]
2 years ago
14

A 3kg plastic tank that has a volume of 0.2m ^3 Is filled with liquid water . Assuming the density of water is 1000kg/m^3 determ

ine the weight of the combined system
Physics
1 answer:
stepan [7]2 years ago
8 0

Answer:

The weight of the combined system is 1989.8 N.

Explanation:

The weight, W, of an object can be expressed as;

W = mg

where m is the mass of the object, and g is the acceleration due to gravity.

Weight of the combined system = weight of tank + weight of water

mass of the plastic tank = 3 kg

weight of the plastic tank = m x g

                               = 3 x 9.8

                               = 29.4 N

Weight of the plastic tank is 29.4 N

But,

density = \frac{mass}{volume}

mass = density x volume

volume of water = 0.2 m^{3}, density of water = 1000 kg/m^{3}.

mass  = 1000 x 0.2

         = 200

mass of water = 200 kg

weight of water = 200 x 9.8

                   = 1960 N

Thus,

combined weight of the system = 29.4 + 1960

                        = 1989.8 N

The weight of the combined system is 1989.8 N.

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Explanation & answer:

Given:

Fuel consumption, C = 22 L/h

Specific gravity = 0.8

output power, P  =  55 kW

heating value, H = 44,000 kJ/kg

Solution:

Calculate energy intake

E = C*P*H

= (22 L/h) / (3600 s/h) * (1000 mL/L) * (0.8 g/mL) * (44000 kJ/kg)

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=55000 / 215111.1

= 0.2557

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Answer:

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