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3 years ago

The number of planets, besides the earth, that are visible to the unaided eye is

Physics

1 answer:

sergejj [24]3 years ago

3 0

The answer should be 5 it’s easy

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A graph that shows how position depends on time is a?

AfilCa [17]

Hello!

A graph that shows how position is depending on time is known as a Position Time Graph.

This is a graph used in Physics to help us understand how motion (positive/negative velocity) changes over a period of time. Motion can be seen in two ways on this graph: constant velocity and changing velocity, otherwise known as acceleration.

Hopes this help you answer your question!

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3 years ago

A trunk rotation is a common dyamic flexibility assessment ture or false

Ilia_Sergeevich [38]

True. It would be false if the statement was "trunk rotation is the most common <em>static</em> flexibility assessment."

So, you're answer should be "true". Hope that helped!

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3 years ago

If a 100 N net force acts on a 50 kg car, what will the acceleration of the car will be?

Allushta [10]

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4 years ago

Suppose a police officer is 1/2 mile south of an intersection, driving north towards the intersection at 40 mph. At the same tim

blagie [28]

Answer:

75.36 mph

Explanation:

The distance between the other car and the intersection is,

$x=x_{0}+V t \\ x=\frac{1}{2}+V t$

The distance between the police car and the intersection is,

$y=y_{0}+V t$

$y=\frac{1}{2}-40 t$

(Negative sign indicates that he is moving towards the intersection)

Therefore the distance between them is given by,

$z^{2}=x^{2}+y^{2}(\text { Using Phythogorous theorem })$

$z^{2}=\left(\frac{1}{2}+V t\right)^{2}+\left(\frac{1}{2}-40 t\right)^{2} \ldots \ldots \ldots(1)$

The rate of change is,

$2 z \frac{d z}{d t}=2\left(\frac{1}{2}+V t\right) V+2\left(\frac{1}{2}-40 t\right)(-40)$

$2 z \frac{d z}{d t}=V+2 V^{2} t-40+3200 t \ldots \ldots \ldots$

Now finding $z$ when $t=0,$ from (1) we have

$z^{2}=\left(\frac{1}{2}+V(0)\right)^{2}+\left(\frac{1}{2}-40(0)\right)^{2}$

$z^{2}=\frac{1}{4}+\frac{1}{4}=\frac{1}{2} \\ z=\sqrt{\frac{1}{2}} \approx 0.7071$

The officer's radar gun indicates 25 mph pointed at the other car then, $\frac{d z}{d t}=25$ when $t=0,$ from

From (2) we get

$2(0.7071)(25)=V+2 V^{2}(0)-40+3200(0)$

$2(0.7071)(25)=V+2 V^{2}(0)-40$

$35.36=V-40$

$V=35.36+40=75.36$

Hence the speed of the car is $75.36 mph$

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3 years ago

Explain the role of good marketing in the success of business

Akimi4 [234]

Answer:

I am joker if you are mad x_________-..............,,,,,,........ €£

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3 years ago