Answer:
C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂
Explanation:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂
The above equation can be balance as illustrated below:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂
There are 16 atoms of H on the left side and 1 atom on the right side. It can be balance by writing 16 before HF as shown below:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + 16HF + CoF₂
There are 3 atoms of F on the left side and a total of 34 atoms on the right side. It can be balance by writing 32 before CoF₃ and 32 before CoF₂ as shown below:
C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂
Now, the equation is balanced.
Answer:
If the volume of a gas increased from 2 to 6 L while the temperature was held constant, <u><em>the pressure of the gas decreased by a factor of 3.</em></u>
Explanation:
Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or
P * V = k
To obtain the proportionality factor k you must make the quotient:

k= 3
This means that <u><em>if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the pressure of the gas decreased by a factor of 3.</em></u>
Answer:

Explanation:
They gave us the masses of two reactants and asked us to determine the mass of the product.
This looks like a limiting reactant problem.
1. Assemble the information
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88
2. Calculate the moles of each reactant

3. Calculate the moles of Pb from each reactant

4. Calculate the mass of Pb
