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lianna [129]
3 years ago
15

Pure gold and silver have densities of 19,300 kg/m^3 and 10,500 kg/m^3, respectively. If a jeweler uses 0.25 cm^3 of metal to ma

ke a ring, then how much heavier (in grams) is the gold ring compared to the silver ring?
Please do not just steal the points from this question. If you need points that badly just go through your stream and steal them from the older unanswered questions.
Physics
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

eusjsdnsbbd

Explanation:

shensnsjsnsnsndndnndndndjdjdjnsnejsjsnsjsjsjnenensnsj

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Novosadov [1.4K]

Answer:

an inverse relationship

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Which data set has the largest range?
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Line the numbers from smallest to largest the subtract the smallest from the largest numbers.

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What is the mass of an object if a force of 34 N produces an acceleration of 4.0 m/s squared​
mrs_skeptik [129]

Answer:

8.5 kg

Explanation:

F = ma

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3 years ago
Read 2 more answers
Calculate the current in a circuit if 500 C of charge passes through it in 10 minutes. *
Sloan [31]

Answer:

Choice a. Approximately 0.83\; \rm A on average.

Explanation:

The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.

Assume that electric charge of size Q flowed through a wire cross-section over a period of time t. The average current in that wire would be:

\displaystyle I = \frac{Q}{t}.

For this question:

  • Q = 500\; \rm C, whereas
  • t = 10\; \rm \text{minutes}.

Therefore, the average current in this circuit would be:

\displaystyle I = \frac{Q}{t} = \frac{500\; \rm C}{10\; \text{minutes}} = 50\; \rm C /\text{minute}.

However, the units in the choices are all in \rm A (for Amperes.) One Ampere is equal to one \rm C / \text{second}. It will take some unit conversations to change the unit of I = 50\; \rm C/ \text{minute} (coulombs-per-minute) to coulombs-per-second.

\begin{aligned}I &= 50\; \rm C/ \text{minute} \\ &= \frac{50\; \rm C}{1\; \rm \text{minute}} \times \frac{1 \; \text{minute}}{60\; \rm \text{seconds}} \approx 0.83\; \rm C/ \text{second} = 0.83 \; \rm A\end{aligned}.

Hence, the most accurate choice here would be choice a.

7 0
3 years ago
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