Answer: 18.9 m
Explanation:
i did the kinematic equation & found the answer.
Answer:
e=mc2 made to relate mass with energy . bcoz energy can neither b created nor b destroyed
Answer:
The correct balanced equation is: 4Al + 3O₂ ➞ 2Al₂O₃
Explanation:
Unfortunately, that isn't the balanced equation. If you take the original equation [unbalanced],
Al + O₂ ➞ Al₂O₃
We have 1 aluminium and 2 oxygen on the left-hand side. On the right-hand side, we have 2 aluminium and 3 oxygen. So we must add 3 on the oxygen in the left-hand side and 2 on the aluminium oxide in the right-hand side.
Al + 3O₂ ➞ 2Al₂O₃
Now if you check, we have 1 aluminium and 6 oxygen on the left-hand side and 4 aluminium and 6 oxygen on the right-hand side. The number of moles of oxygen is equal but the number of moles of aluminium isn't. So we must add 4 on the aluminium of the left-hand, in order to have a balanced equation.
4Al + 3O₂ ➞ 2Al₂O₃
Answer:
true 1
2 is false 2. 3 . 4. 5
Explanation:
For this exercise, let's calculate the different parameters and analyze the corresponding statements.
the resistance of each wire
R = ρ
wire B.
has a diameter of d₀
therefore its radius is r₀ = d₀ / 2
the area is A = pi r₀²
A = π d₀²/ 4
we subtitle
Ro = ρ
R_b = R₀
wire A
the diameter is d = 2d₀
therefore the radius is r = d/2
r = d₀
resistance is
R_a = ρ
R_a = 4 R₀
when examining the answers
1 is true
4 is false
Now let's calculate the power
P = V I
V = I R
P = V² / R
as they indicate that the cables are connected in parallel, the voltage in them is the same, therefore the potency depends on the resistance
wire B
P = V² / R_b
P_b = V² / R₀
wire A
P_a = v² / R_a
P_a = V² / 4R₀
P_a = ¼ P_b
2 is false
in a parallel circuit the waves are the same therefore
3 False
ohm's law is
V = I r
I = V / R
wire B
I_b = V / R_b
I_b = V / Ro
wire
I_a = V / R_a
I_a = V / 4 Ro
I_a = ¼ I_a
5 is false
You would need to connect a potential difference across a resistor in parallel