To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.
If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,
So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb
Answer:
Muscle contraction thus results from an interaction between the actin and myosin filaments that generates their movement relative to one another. The molecular basis for this interaction is the binding of myosin to actin filaments, allowing myosin to function as a motor that drives filament sliding.
One of the useful forns of the formula for electrical power is: Power = (voltage squared) / (resistance). Knowing that power is proportional to (voltage squared), we can see that if the voltage is reduced to 1/2, the power is reduced to 1/4 of its original value. The 220volt/60watt appliance, when operated on 110 volts, dissipates 60/4 = 15 watts.
Answer:
Watts=Volt*Amps
So A=570/120=4.75amps
If voltage drops to 110V We get A=570/110=5.(18...)amps
Neap tide = tide where there is the least difference between high and low water levels
Spring tide = tide where there is the greatest difference between high and low water levels
Equator = an imaginary line drawn around earth dividing it into northern and southern hemispheres
Seasons = the divisions of the year marked by specific weather patterns and daylight hours.
Hope this helps!
