<h2>Answer:</h2>
<h2>Explanation:</h2>
First, let's refer to the distance formula:
, where d is distance, v is velocity or speed and t is time.
Now, let's find the distance covered by each individual speed that the car had:
<h3>1. Speed 1.</h3>
In order to use the formula, we need to convert minutes into hours since the speed is given in km/h.
21.1 min/60= 0.35 h.
Now, apply the distance formula.
d=(0.35h)*(86.8km/h)= 30.38 km.
<h3>2. Speed 2.</h3>
Convert minutes to hours again and do the same calculations.
10.6min/60=0.18h
d=(0.18h)*(106km/h)= 19.08 km.
<h3>3. Speed 3.</h3>
36.5min/60= 0.61h
d=(0.61h)*(30.9km/h)= 18.85 km.
<h3>4. Obtain the total distance.</h3>
The total distance must be given by the addition of all individual distances traveled by the car on each speed:
Total distance= 30.38 km + 19.08 km + 18.85 km= 68.31 km.
Answer:
zero
Explanation:
Consider two identical wave pulses on a rope having a fixed end. Suppose the first pulse reaches the end of the rope, is reflected back, and then meets the second pulse, both waves will be out of phase by π radians. Therefore, they form destructive interference and hence the amplitude of the resultant pulse would be zero.
Answer:
i think it Naturalistic observation
Explanation:
If <em>A</em> = <em>i</em> - <em>j</em> + <em>k</em>, then the magnitude of <em>A</em> is
||<em>A</em>|| = √(1² + (-1)² + 1²) = √3
Then the unit vector in the direction of <em>A</em> is 1/||A|| multiplied by <em>A</em> :
<em>u</em> = <em>A</em>/||<em>A</em>|| = (<em>i</em> - <em>j</em> + <em>k</em>)/√3
(choice D)
<span>The
heavier the body is, the stronger its gravitational pull. Example, the Milky Way
Galaxy has a gravitational pull because of the heavenly bodies such as stars and planets are surrounding it. A strong force is exerted if the mass of another body is bigger than the other body.</span>
