1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Furkat [3]
4 years ago
9

How to find the gradient of a velocity time graph

Physics
1 answer:
Sidana [21]4 years ago
7 0
The area-

The area under the line in a velocity-time graph represents the distance travelled. To find the distance travelled in the graph above, we need to find the area of the light-blue triangle and the dark-blue rectangle.

<span><span>Area of light-blue triangle -
<span>The width of the triangle is 4 seconds and the height is 8 meters per second. To find the area, you use the equation: <span>area of triangle = 1⁄2 × base × height </span><span>so the area of the light-blue triangle is 1⁄2 × 8 × 4 = 16m. </span></span></span><span> Area of dark-blue rectangle The width of the rectangle is 6 seconds and the height is 8 meters per second. So the area is 8 × 6 = 48m.</span><span> Area under the whole graph <span>The area of the light-blue triangle plus the area of the dark-blue rectangle is:16 + 48 = 64m.<span>This is the total area under the distance-time graph. This area represents the distance covered.</span></span></span></span>
You might be interested in
When a manufacturer intentionally misleads customers by only revealing part of the truth about the evidence that supports a prod
torisob [31]
The answer would be A. failure to close
7 0
3 years ago
When using the lens equation, a negative value as the solution for di indicates that the image is
nirvana33 [79]

Answer:

The Anatomy of a Lens

Refraction by Lenses

Image Formation Revisited

Converging Lenses - Ray Diagrams

Converging Lenses - Object-Image Relations

Diverging Lenses - Ray Diagrams

Diverging Lenses - Object-Image Relations

The Mathematics of Lenses

Ray diagrams can be used to determine the image location, size, orientation and type of image formed of objects when placed at a given location in front of a lens. The use of these diagrams was demonstrated earlier in Lesson 5 for both converging and diverging lenses. Ray diagrams provide useful information about object-image relationships, yet fail to provide the information in a quantitative form. While a ray diagram may help one determine the approximate location and size of the image, it will not provide numerical information about image distance and image size. To obtain this type of numerical information, it is necessary to use the Lens Equation and the Magnification Equation. The lens equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f)

3 0
3 years ago
Describa con sus palabras que fue lo que descubrio galileo en su legendario experimento en la torre inclinada de pisa
german

Answer:

En 1589 Galileo realizó un experimento lanzando dos bolas de diferentes masas desde la famosa Torre Inclinada de Pisa para demostrar que el tiempo de caída es independiente de la masa de la bola. A través de este experimento, Galileo descubrió que los cuerpos caían casi simultáneamente, refutando la teoría de Aristóteles de que la tasa de caída era proporcional a la masa del cuerpo.  

Debido a la imperfección de los equipo de medición de esa época, la caída libre de los cuerpos era casi imposible de estudiar. En busca de una forma de reducir la velocidad de movimiento, Galileo reemplazó la caída libre por rodar sobre una superficie inclinada, donde había velocidades y resistencia del aire significativamente más bajas. Se notó que con el tiempo, la velocidad del movimiento aumenta: los cuerpos se mueven con aceleración. Se concluyó que la velocidad y la aceleración no dependen ni de la masa ni del material de la pelota.

 

5 0
3 years ago
What are conductors and insulators? Give at least five example of each ​
Leona [35]

Answer: conductors are substances that allow heat or electricity to pass through . It deals with only the flow of electrons.

Eg. water, copper wire, iron rod, some ceramic materials, metallic nail.

Insulators are materials that do not allow heat or electricity to pass through.

Eg. Book, plastic, rubber, glass, paper

Explanation:

8 0
3 years ago
What invisible force will cause you to fall to the earth if you fall off your bed?
Katyanochek1 [597]

Answer:

The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.

Explanation:

your welcome

8 0
3 years ago
Other questions:
  • An electron is moving at 7.4 x 10^5 m/s perpendicular to a magnetic field. It experiences a force of -2.0 x 10^-13 N. What is th
    12·1 answer
  • Electronic signals that pulse current in a series of ones and zeros are known as
    10·1 answer
  • The table below shows the acceleration of gravity on different bodies in the solar system.
    14·2 answers
  • The gage pressure of an automobile tire is measured to be 210kPa before a trip and 220kPa after the trip at a location where the
    10·1 answer
  • Which of the following have exactly 5 significant figures?
    9·1 answer
  • A 1200 kg car carrying four 80 kg people travels over a rough "washboard" dirt road with corrugations 4.0 m apart which causes t
    14·1 answer
  • Focus Question: What are SI units, and why are they used?
    6·1 answer
  • In lab you find that a 1-kg rock suspended above water weighs 10 N. When the rock is suspended beneath the surface of the water,
    9·1 answer
  • A crate of books rests on a level floor. To move it along the floor at a constant velocity, why do you exert less force if you p
    8·1 answer
  • figure shows four situations in which a horizontal net force acts on the same block which is initially at rest
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!