Answer:
3.36 Joules
Explanation:
Work done= Force × distance
F=4.2 N
distance= 0.8 m
work done= 4.2 × 0.8
work done= 3.36 Joules
Answer:
the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Explanation:
Given the data in the question;
Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J
Mass of proton = 1.673 × 10⁻²⁷ kg
Charge of proton = 1.602 × 10⁻¹⁹ C
distance d = 2 m
we know that
Kinetic Energy = Charge of proton × Potential difference ΔV
so
Potential difference ΔV = Kinetic Energy / Charge of proton
we substitute
Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )
Potential difference ΔV = 20287.14 V
Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;
E = Potential difference ΔV / distance d
we substitute
E = 20287.14 V / 2 m
E = 10143.57 V/m or 1.01 × 10⁴ V/m
Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
An electric force exists between the following:
-Two negative objects
-Two positive objects
-A negative object and a positive object
√10(√10) = √10^2
The root and the square cancels:
√10^2 = 10
10 is your answer
hope this helps
The infrared<span> (</span>IR<span>) and the </span>ultraviolet(UV<span>) represent the two extremities of the visible spectrum (400-700nm). While </span>IR<span> represents electromagnetic radiation
with wavelengths longer than those of visible </span>light<span>, </span>UV<span> represents wavelengths
shorter than visible </span>light<span>.
</span><span>
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