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Answer:
the electric field strength of this charge is two times the strength of the other charge
Explanation:
Using the relationship between electric field and the charge, which is inversely proportionality. Let the the magnitude of the first charge be Q and the respective electric field be E. It implies that;
E1/E2 = Q2/Q1
E2 = E1 x Q1/Q2
= E x Q/ (Q/2)
= 2E
The recoil velocity of the astronaut is -0.070 m/s
Explanation:
We can solve this problem by using the principle of conservation of momentum: in fact, in absence of external forces, the total momentum of the astronaut-wrench system must be conserved.
At the beginning, their total momentum is zero:
(1)
Later, after the astronaut throws the wrench, the total momentum is
(2)
where
m = 0.725 kg is the mass of the wrench
v = 13.8 m/s is the velocity of the wrench
M = 143 kg is the mass of the astronaut
V is the recoil velocity of the astronaut
Since momentum is conserved, (1) = (2), and so we can find V:
Learn more about momentum:
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Answer:
v' = 1.5 m/s
Explanation:
given,
mass of the bullet, m = 10 g
initial speed of the bullet, v = 300 m/s
final speed of the bullet after collision, v' = 300/2 = 150 m/s
Mass of the block, M = 1 Kg
initial speed of the block, u = 0 m/s
velocity of the block after collision, u' = ?
using conservation of momentum
m v + Mu = m v' + M u'
0.01 x 300 + 0 = 0.01 x 150 + 1 x v'
v' = 0.01 x 150
v' = 1.5 m/s
Speed of the block after collision is equal to v' = 1.5 m/s
