Question

How many molecules are present in 936 g of glucose (C6H12O6)? (The molar mass of glucose = 180.16 g/mol.)

Answer 1

Number of moles glucose:

936 / 180.16 = 5.1953 moles

1 mole --------------- 6.02 x 10²³ molecules
5.1953  moles ----- ?

= 5.1953 * 6.02 x 10²³  / 1

= 3.1275 x 10²⁴ molecules

hope this helps!

Answer 2

Answer: The number of molecules present in given amount of glucose are $31.28429\times 10^{23}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Mass of glucose = 936 g

Molar mass of glucose = 180.16 g/mol

Putting values in above equation, we get:

$\text{Moles of glucose}=\frac{936g}{180.16g/mol}=5.195mol$

Now, according to the mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 5.19 moles of a compound will contain $5.195\times 6.022\times 10^{23}=31.28429\times 10^{23}$ number of molecules.

Hence, the number of molecules present in given amount of glucose are $31.28429\times 10^{23}$