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Alja [10]
3 years ago
13

Which one would be expected to happen? If one of the buffers that contribute to pH stability in human blood is carbonic acid (H2

CO3). Carbonic acid is a weak acid that when placed in an aqueous solution dissociates into a bicarbonate ion (HCO3-) and a hydrogen ion (H+). Thus, H2CO3 HCO3- + H+ If the pH of the blood increases.
A. A decrease in the concentration of HC03- and an increase in the concentration of both H2CO3 and H2O
B. An increase in the concentration of H2CO3 and a decrease in the concentration of H2O
C. An increase in the concentration of HCO3- and a decrease in the concentration of H2O
D. A decrease in the concentration of H2CO3 and an increase in the concentration of H2O
E. A decrease in the concentration of HCO3- and an increase in the concentration of H2O
Chemistry
1 answer:
vredina [299]3 years ago
5 0

Answer:

The correct answer is option C.

Explanation:

H_2CO3+H_2O\rightleftharpoons HCO_3^{-} + H_3O^+

On increasing the pH of the blood the hydronium ions concentration will decrease which will result in decrease in concentration of hydronium ions at the equilibrium state of hydrogen carbonate.

Le-Chatelier's principle:

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

According to Le-Chatelier's principle , on decrease in a concentration of the product the equilibrium moves in forward correction to re-establish itself.

So, on increasing the pH, the hydronium ions concentration will decrease which results in disassociation of more hydrogen carbonate to maintain the pH of the blood.

Hence, the correct answer is option C.

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Absalon adds 1 g of salt to 1 L of room temperature water (25 °C). Then, he starts a timer and observes what happens. He notices
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Answer:

B

Explanation:

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What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HC
Mkey [24]

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

Mass of Na3PO4 = molar mass × number of moles

= 0.0013 × 164

= 0.219 g

Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

= 0.219 × 50 g/100 g

= 0.109 g.

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3 years ago
Can you make the particles of any of the substances stop moving?
ser-zykov [4K]

The particles cannot move around at all. The particles are, however, still in motion.

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Write and balance the half-reaction for the oxidation of white phosphorous P4 to the phosphate ion PO3^−4 in a basic solution.
aalyn [17]

Since the half-reaction is occurring in a basic solution, add 32OH− to each side of the equation to eliminate the H+ ions.

P₄ +16H₂O + 32OH⁻ ⟶ 4PO₃⁻⁴ + 32H⁺ +32OH⁻

Final reaction :

P₄ + 32OH⁻ ⟶ 4PO₃⁻⁴ + 16H₂O + 20e⁻

A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.

The concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).

Half-reactions are often used as a method of balancing redox reactions. For oxidation-reduction reactions in acidic conditions, after balancing the atoms and oxidation numbers, one will need to add H+ ions to balance the hydrogen ions in the half reaction.

For oxidation-reduction reactions in basic conditions, after balancing the atoms and oxidation numbers, first treat it as an acidic solution and then add OH- ions to balance the H+ ions in the half reactions (which would give H2O).

Learn more about Half reactions here : brainly.com/question/2491738

#SPJ4

3 0
2 years ago
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