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jolli1 [7]
3 years ago
6

For real gases, how does a change in pressure affect the ratio of PV to nRT?

Chemistry
2 answers:
nadya68 [22]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

Molecules of a real gas are smaller is size and occupy volume or space. Real gases do not behave like ideal gases.

Mathematically, ratio of \frac{PV}{nRT} is either greater than or smaller than 1.

Hence, when there is increase in pressure then there will be increase in ratio. On the other hand, if there is decrease in ratio then there will be decrease in ratio.

Thus, we can conclude that for real gases, a change in pressure affect the ratio of PV to nRT because the ratio increases as pressure increases.

romanna [79]3 years ago
3 0
A the ratio decreases as pressure increases
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22 would be the answer
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If the initial [NO2] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M. If the initial is 0.260 , it
Nitella [24]

The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

NO_2\rightarrow NO+\frac{1}{2}O_2

The reaction is second order for NO_2 with a rate constant of 0.543M^{-1}s^{-1} at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M

a) 1.01    b) 5.19     c) 0.299      d) 0.0880     e) 3.34

<u>Answer:</u> The time taken is 5.19 seconds

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.543M^{-1}s^{-1}

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.150 M

[A]_o = Initial concentration = 0.260 M

Putting values in above equation, we get:

0.543=\frac{1}{t}\left (\frac{1}{(0.150)}-\frac{1}{(0.260)}\right)\\\\t=5.19s

Hence, the time taken is 5.19 seconds

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3 years ago
The endocrine system is made of which components?
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How many sub-energy levels does the 2nd MEL have?
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Answer:

n=  | Shell            |       Maximum Number of Electrons

1    | 1st Shell      |      2

2   | 2nd Shell      |      8

3   | 3rd Shell        |      18

4   |  4th Shell        |      32

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3 years ago
A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
dezoksy [38]

Answer:

25°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

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5.682 = 142.128/T₂

T₂ = 142.128/5.682

T₂ = 25.0137272756°C = 25°C

6 0
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