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jolli1 [7]
3 years ago
6

For real gases, how does a change in pressure affect the ratio of PV to nRT?

Chemistry
2 answers:
nadya68 [22]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

Molecules of a real gas are smaller is size and occupy volume or space. Real gases do not behave like ideal gases.

Mathematically, ratio of \frac{PV}{nRT} is either greater than or smaller than 1.

Hence, when there is increase in pressure then there will be increase in ratio. On the other hand, if there is decrease in ratio then there will be decrease in ratio.

Thus, we can conclude that for real gases, a change in pressure affect the ratio of PV to nRT because the ratio increases as pressure increases.

romanna [79]3 years ago
3 0
A the ratio decreases as pressure increases
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marin [14]

Answer:

[A]²

Explanation:

Since the formation is independent of D, D is 0 order.

Since a quadruples when it is doubled it can be written as

2A^X= 4

To find the unknown power we can assume A= 1 to make the math simple. So When a = 2 (Because you doubled it) raised to X power it will equal 4

so the unknown power is 2

Making the rate law

[a]²[b]⁰

or simply just

[A]²

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When one atom of carbon reacts with two atoms of oxygen, they combine to form one molecule of carbon dioxide. How many atoms of
tankabanditka [31]

The equation is: C+O2=>CO2

Since we got 10 molecules of CO2 new balanced equation would be 10C+10O2=>10CO2

from this equation we can see that we have 10 molecules of oxygen, however ,we need to find atoms. There are 2 atoms in the oxygen molecule so we need to multiply 10 by 2 which gives us 20 atoms.

The answer: there are 20 atoms of oxygen

4 0
3 years ago
A system gains 652 kJ of heat, resulting in a change in internal energy of the system equal to +241 kJ. How much work is done?
levacccp [35]

Answer:

-411 kj

Explanation:

We solve by using this formula

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Putting the value into the equation

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Workdone = 241 - 652

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Since work done is negative it means that work was done by the system

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