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otez555 [7]
3 years ago
11

A spool of thread, free to unwind, is on a horizontal surface (with friction) and pulled directly upward (+y) at all times. The

spool rolls without slipping on the floor. The spool has a mass M, moment of inertia I, and a radius of R. Assume the string is wrapped around the spool at a radius r (where r < R). spool rolling on the floor
Which equation below is a correct expression of Newton’s Second Law ( ΣF=ma ) in the x (horizontal) -direction for this situation. Assume all the forces below are magnitudes and that to the right is considered the positive direction.

a. F_T - Ff= Max
b. F_T+Ff= Max
c. Ff= Max

Physics
1 answer:
k0ka [10]3 years ago
6 0

Answer:

The Correct Answer is "D"

Explanation:

For Detail of this answer Please see the attached file.

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What speed would a fly with a mass of 0.72 g need in order to have the same kinetic energy as a 1250 kg automobile traveling at
Elena L [17]
Kinetic of automobile

Mass m = 1,250 Kg;         V = 11 m/s

Formula: K.E = 1/2 mV²

               K.E = 1/2(1,250 Kg)(11 m/s)²

               K.E = 75,625 J

Speed required for insect to have the same kinetic energy as automobile

Mass of insect = 0.72 g convert to Kg   m = 7.2 x 10⁻⁴ Kg

K.E = 1/2 mV²  Derive V =?

 V = 2 K.E/m

 V = √2(75,625 J)/7.2 x 10⁻4 Kg

 V = √2.1 x 10⁸ m²/s²

 V = 14,491.34 m/s  (velocity of insect)









5 0
3 years ago
What is the weight of a<br> 63.7 kg person?
IRINA_888 [86]

Answer:

A person that weighs 63.7 kg weighs 63.7 kg

Explanation:

Too complicated to explain.

6 0
2 years ago
Read 2 more answers
The resistance of the body varies from approximately 500 kΩ (when it is very dry) to about 1.20 kΩ (when it is wet). The maximum
scoray [572]

Answer:

a) The maximum potential difference the wet human body can take = 5.88 V

b) This value is very much lower than the normal voltage of household outlets (120 V) and isn't in the same range at all.

This means one should be very careful operating electrical appliances (even at home) while the body is wet.

Explanation:

From Ohm's law, V = IR

The resistance of the body when the body is wet = 1.2 kΩ = 1200 Ω

Maximum safe current that the body can withstand = 4.90 mA = 0.0049 A

Maximum voltage the body can withstand while wet = (Maximum safe current that the body can withstand) × (Resistance of the body when the body is wet) = 0.0049 × 1200 = 5.88 V

b) This value is still very much lower than the normal voltage of household outlets (120 V) and isn't in the same range at all.

This means one should be very careful operating electrical appliances (even at home) while the body is wet.

4 0
3 years ago
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Guys they deleted my account i was charliecole7 i had to make a new one
xxTIMURxx [149]

Answer: ok???

Explanation:

4 0
3 years ago
Read 2 more answers
A question for the physicists out there:
Tomtit [17]
I don't think that's exactly what this website is here for. / / / The average current = 30 C / 120 sec = 250 mA. / / / 1 volt = 1 joule/coulomb ... 30 C x 1.5 x 10^6 J/C = 4.5 x 10^7 joules per stroke. / / / Apoligies for the formatting. Some websites recognize a CR-LF from a mobile device, and others don't.
7 0
3 years ago
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