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otez555 [7]
3 years ago
11

A spool of thread, free to unwind, is on a horizontal surface (with friction) and pulled directly upward (+y) at all times. The

spool rolls without slipping on the floor. The spool has a mass M, moment of inertia I, and a radius of R. Assume the string is wrapped around the spool at a radius r (where r < R). spool rolling on the floor
Which equation below is a correct expression of Newton’s Second Law ( ΣF=ma ) in the x (horizontal) -direction for this situation. Assume all the forces below are magnitudes and that to the right is considered the positive direction.

a. F_T - Ff= Max
b. F_T+Ff= Max
c. Ff= Max

Physics
1 answer:
k0ka [10]3 years ago
6 0

Answer:

The Correct Answer is "D"

Explanation:

For Detail of this answer Please see the attached file.

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The nutritional calorie (Calorie) is equivalent to 1 kcal. One pound of body fat is equivalent to about 4.1 x 103 Calories. If a
Luba_88 [7]

Answer:

t = 70.13 hours

Explanation:

As we know that 1 lb fat can be used to expend 4.1 k Calorie of energy

so here we know that we have to use 7.56 lb of body fat

so here the total energy that is to be utilized is given as

Q = (4.1 \times 10^3)(7.56)

so we will have

Q = 30996 Calorie

now we know that runner expends the energy at rate of 1850 kJ/h

so we have

E = 1850 \times 10^3 kJ/h

so it is

E = 0.44 \times 10^3 calorie/h

now we know that time to burn this energy is given as

t = \frac{Q}{E}

t = \frac{30996}{0.44 \times 10^3}

t = 70.13 hours

5 0
3 years ago
1. What do you notice from the picture?<br>2. Did anyone get the correct answer? ​
Fudgin [204]

Answer:

1. I notice nothing because is no picture it probably didnt work

2. idk

6 0
3 years ago
An 80-kg football player travels to the right at 8 m/s and a 120-kg player on the opposite team travels to the left at 4.0 m/s.
77julia77 [94]

Answer:

See Explanation

Explanation:

m1(v1) + m2(v2)

Opposite turns the plus to subtraction.

80(8) - 120(4.0)

60 - 480 = 160 kg m/s to the right

7 0
2 years ago
A car starts from rest and accelerates along a straight line path in one minute. It finally attains a velocity of 40 meters/seco
romanna [79]

Answer:

it's A

Explanation:

I JUST A FROM THE TOPIC

7 0
3 years ago
In the lab you place a beaker that is half full of water (density pw ) on a scale. You now use a light string to suspend a piece
Radda [10]

Answer:

N2- N1 = \rho_{w}  V g

Explanation:

Let's use for this exercised the equilibrium relationship

        ∑ F = 0

        N -W = 0

        N = W = mg

Let's use density redefinition

       ρ = m / v

       m = ρ V

       N₁ = (ρ V) g

Repeat for when the liquid is submerged, in this case an upward thrust appears as a result of the water dispensed (rgow)

        N₂ + B - W = 0

        N₂ = W - B

        B = m_{water} g

        \rho_{w} = m / V

         m_{w}  =  \rho_{w}  V

        N = ρ V g -  \rho_{w}  Vg

        N2 = N1 +   \rho_{w}  V g

        N2- N1 = \rho_{w}  V g

6 0
4 years ago
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