A spool of thread, free to unwind, is on a horizontal surface (with friction) and pulled directly upward (+y) at all times. The
spool rolls without slipping on the floor. The spool has a mass M, moment of inertia I, and a radius of R. Assume the string is wrapped around the spool at a radius r (where r < R). spool rolling on the floor
Which equation below is a correct expression of Newton’s Second Law ( ΣF=ma ) in the x (horizontal) -direction for this situation. Assume all the forces below are magnitudes and that to the right is considered the positive direction.
a. F_T - Ff= Max
b. F_T+Ff= Max
c. Ff= Max
Which equation below is a correct expression of Newton’s Second Law ( ΣF=ma ) in the x (horizontal) -direction for this situation. Assume all the forces below are magnitudes and that to the right is considered the positive direction.
a. F_T - Ff= Max
b. F_T+Ff= Max
c. Ff= Max
1 answer:
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Answer:
See answer
Explanation:
The area of the circular loop is given by:
The magnetic flux is given by:
is parallel to
and
is constant in magnitude and direction therefore:
Part A)
initially the flux is
after the interval
the flux is
now, the EMF is defined as:
,
if we consider very small then we can re-write it as:
then:
Part B)
When looked down from above, the current flows counter clockwise, according to the right hand rule, if you place your thumb upwards (the direction of the magnetic field) and close your fingers, then the current will flow in the direction of your fingers.