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jolli1 [7]
3 years ago
8

The nutritional calorie (Calorie) is equivalent to 1 kcal. One pound of body fat is equivalent to about 4.1 x 103 Calories. If a

runner expends 1850 kJ/h, how long (h) does she have to run to work off 7.56 lb of body fat? Enter your answer in decimal format with one decimal place.
Physics
1 answer:
Luba_88 [7]3 years ago
5 0

Answer:

t = 70.13 hours

Explanation:

As we know that 1 lb fat can be used to expend 4.1 k Calorie of energy

so here we know that we have to use 7.56 lb of body fat

so here the total energy that is to be utilized is given as

Q = (4.1 \times 10^3)(7.56)

so we will have

Q = 30996 Calorie

now we know that runner expends the energy at rate of 1850 kJ/h

so we have

E = 1850 \times 10^3 kJ/h

so it is

E = 0.44 \times 10^3 calorie/h

now we know that time to burn this energy is given as

t = \frac{Q}{E}

t = \frac{30996}{0.44 \times 10^3}

t = 70.13 hours

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If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 41 N · m, what minimum f
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We have that the Force  is mathematically given as

F=170.833N

<h3></h3><h3>Force </h3>

Question Parameters:

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Generally the equation for the Force   is mathematically given as

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imagine a square column of the atmosphere, 10 m on a side, that extends all the way to the top of the atmosphere.
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The calculated weight in newtons is 10 N.

Listed below is the data we will use:

Area A is where the pressure is P. Here are the details we were given:

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Do the area conversion to square meters.

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From the definition of pressure, calculate the weight of the air column. In this instance, the air column's weight is determined by multiplying the atmospheric pressure by the air column's base area.

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