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jolli1 [7]
3 years ago
8

The nutritional calorie (Calorie) is equivalent to 1 kcal. One pound of body fat is equivalent to about 4.1 x 103 Calories. If a

runner expends 1850 kJ/h, how long (h) does she have to run to work off 7.56 lb of body fat? Enter your answer in decimal format with one decimal place.
Physics
1 answer:
Luba_88 [7]3 years ago
5 0

Answer:

t = 70.13 hours

Explanation:

As we know that 1 lb fat can be used to expend 4.1 k Calorie of energy

so here we know that we have to use 7.56 lb of body fat

so here the total energy that is to be utilized is given as

Q = (4.1 \times 10^3)(7.56)

so we will have

Q = 30996 Calorie

now we know that runner expends the energy at rate of 1850 kJ/h

so we have

E = 1850 \times 10^3 kJ/h

so it is

E = 0.44 \times 10^3 calorie/h

now we know that time to burn this energy is given as

t = \frac{Q}{E}

t = \frac{30996}{0.44 \times 10^3}

t = 70.13 hours

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Explanation:

hope this helps

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The force of gravity acting<br> on a child's mass on earth is 490 newtons. what's the child's mass?
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What we know:
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3 years ago
Two lightbulbs have powers P1 and P2 when separately connected across an ideal battery with potential difference ΔV. The bulbs a
jarptica [38.1K]

Answer:

P'=\dfrac{P_1P_2}{P_1+P_2}

Explanation:

Lets take

Resistance of bulb 1 =R₁

Resistance of bulb 2 =R₂

As we know that power P

P= ΔV²/R

Given that voltage difference is same for both bulbs

So

P₁R₁= ΔV²       --------1

P₂R₂= ΔV²   -----------2

When these resistance are connected in series then equivalent resistance R

R=R₁+ R₂

The new power P'

P'=ΔV²/R

P'R=ΔV²   ------3

From equation 1 ,2 and 3

P'(R₁+ R₂) = ΔV²

P'\left(\dfrac{\Delta V^2}{P_1}+\dfrac{\Delta V^2}{P_2}\right)=\Delta V^2

P'=\dfrac{P_1P_2}{P_1+P_2}

6 0
3 years ago
A bullet is shot from a rifle with a velocity of 720.0 m/s what time is required for the bullet to strike a target 324.0m to the
Basile [38]

The bullet will strike the target placed in 324.0 m in the East in 0.45 seconds.

<u>Explanation:</u>

As we all know the epic relation between distance, speed and time; we cam easily estimate the time in which an object can reach to the destination or target.

As here in this case, we know the distance of the target and the velocity of a bullet exerted from a rifle given as follows,

Distance of the Target from the rifle edge = 324.0 m

Velocity of bullet exerted from the rifle = 720 m/s

Since we know that,

      \text {velocity}=\frac{\text {distance}}{\text {time}}

or

       \text {Time}=\frac{\text {distance}}{\text {velocity}}

We can simply implement all the values in the formula and get the results i.e the time required by the bullet to hit the target. Since both the values are in S.I units measures, we don't need to change or convert any of them. Hence,

       \text { Time }=\frac{324}{75}=0.45 \text { seconds }

Therefore, the bullet will hit the target in 0.45 seconds.

4 0
3 years ago
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