3 years ago

Which action will cause the induced current to decrease or remain constant?

Physics

1 answer:

lukranit [14]3 years ago

4 0

Answer:

Its Reversing the polarity of the magnet :)

Explanation:

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Please help, thank you !

kherson [118]

Answer:

0.04658 m from the nut

Explanation:

Recall that torque is defined as the vector product of force (F) times distance (d). Then, given that the force is applied perpendicular to the wrench, gives the sine of the angle (90 degrees) equal to 1, simplifying the calculation which consists basically on solving for d in the equation:

2.25 N*m = 48.3 N * d

d = 2.25 /48.3 m ≈ 0.04658 m

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3 years ago

Find the net gravitational force fnet acting on the earth in the sun-earth-moon system during the new moon (when the moon is loc

Lina20 [59]

After thorough researching, the net gravitational force Fnet acting on the earth in the sun-earth-moon system during the new moon and when the moon is located directly between the earth and the sun is 3.50x10^22 N. The correct answer to the following given statement above is 3.50x10^22 N.

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4 years ago

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How would a small bar magnet be oriented when placed at position X

Alex Ar [27]

The answer is right here

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3 years ago

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(No files or links) Which of the following is a defining property of gases?

MariettaO [177]

The answer for this is d

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3 years ago

A toy car of mass 8 kg initially moves with a speed of 5 m/s. How much work must be done on the car to increase its speed to 10

sukhopar [10]

ANSWER:

300 J

STEP-BY-STEP EXPLANATION:

To know the work required, we must calculate the work in both cases, the difference would be the amount of work necessary for the speed to increase. The work done is the same as the amount of energy increase. The formula for kinetic energy is:

$\frac{1}{2}m\cdot v^2$

We calculate in each case:

$\begin{gathered} \frac{1}{2}\cdot8\cdot10^2=400\text{ J} \\ \frac{1}{2}\cdot8\cdot5^2=100\text{ J} \end{gathered}$

We calculate the difference between the two to find out the work required:

$400-100=300\text{ J}$

The work required is 300 J

3 0

2 years ago