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2 years ago

6

Which action will cause the induced current to decrease or remain constant?

1 answer:

lukranit [14]2 years ago

4 0

Answer:

Its Reversing the polarity of the magnet :)

Explanation:

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A source charge of 3 µC generates an electric field of 2.86 × 105 N/C at the location of a test charge. Using k = 8.99 × 109N.m^

Nataliya [291]

Variables:

Source charge, Q = 3 micro C = 3 * 10^ - 6 C

E = electric field = 2.86 * 10 ^5 N/C

K = 8.99 * 10^9 N * m^2 / C

d = distance = ?

Formula:

E = K * Q / (d^2) => d^2 = K * Q / E

=> d^2 = 8.99 * 10^9 N * m^2 / C * 3 * 10^ -6 C / (2.86 * 10^ 5 N/C)

d^2 = 9.43 * 10 ^ -2 m^2

=> d = 3.07 * 10^-1 m

Answer: 0.307 m

Note: it is a long distance due to the Electric field is very low

7 0

2 years ago

Read 2 more answers

A 5.0 kg block hangs from a spring with spring constant 2000 N/m. The block is pulled down 5.0 cm from the equilibrium position

Svet_ta [14]

Answer:

Explanation:i think this would help u

7 0

2 years ago

Gravity is greater when there is

liberstina [14]

Gravity is greater when there is more mass and less distance between two given objects.

7 0

2 years ago

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The box is pushed to the left with 30 N of force, but does not move. What is the Friction Force?

Andrews [41]

However here coefficient of friction is not given so unable to calculate.

You can calculate it by below formula.

The formula given by

$\\ \sf\longmapsto F_f=\mu N$

Or

$\\ \sf\longmapsto F_f=\mu mg$

u is coefficient of friction

N is normal reaction.

Here..

box doesn't move means the force if limiting friction is greater than applied force.

5 0

1 year ago

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The third-order bright fringe of 610-nm light is observed at an angle of 31° when the light falls on two narrow slits. How far a

Anna11 [10]

Answer:

The distance between the slits is 3.55 μm

Explanation:

Given that,

Order number = 3

Wave length = 610 nm

Angle = 31°

We need to calculate the distance between the slits

Using formula of distance of slit

$d\sin\theta=n\lambda$

$d=\dfrac{n\lambda}{\sin\theta}$

Where, n = order number

$\lambda$ = wavelength

Put the value into the formula

$d=\dfrac{3\times610\times10^{-9}}{\sin31}$

$d=3.55\times10^{-6}\ m$

$d= 3.55\ \mu m$

Hence, The distance between the slits is 3.55 μm.

8 0

3 years ago