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tangare [24]
3 years ago
13

Which statement provides the best argument in favor of deforestation?

Physics
2 answers:
Salsk061 [2.6K]3 years ago
6 0
The last option would be I think
viktelen [127]3 years ago
5 0

Answer: Deforestation opens up land for mining and cattle ranching.

Explanation:

The cutting of trees on large in a forest is known as deforestation. Deforestation is done to clear up land for industrial purposes - mining, cattle ranching, to build up homes. Thus, to accommodate the needs of growing population, deforestation is done. This is the best argument in favor of deforestation because otherwise, deforestation affects climate around the globe, leads to soil erosion and causes pollution.  

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The amount of heat needed to increase the temperature of a 1-kilogram substance by 1°C is known as the
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The amount of heat needed to increase the temperature of a 1-kilogram substance by 1°C is known as the specific heat of the substance.

the formula for specific heat of a substance is given as

c = Q/(m ΔT)

where Q = Heat required to change the temperature by 1°C

m = mass of the substance

ΔT = change in temperature.

the units of specific heat is given as Joules/(kilogram °C)


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3 years ago
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The table below shows the average wind speeds of four hurricanes in Florida
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Learning Goal: To review the concept of conservative forces and to understand that electrostatic forces are, in fact, conservati
CaHeK987 [17]

Explanation:

The electrostatic forces are conservative forces!

The mainly property of the conservative fields is \vec{\nabla} \times \vec E=\vec 0

In spherical coordinates the field's expression is:

\vec E=\frac{Q}{4\pi \epsilon _0 r^2} .\^r

and the curl expression is:

\nabla\times \vec E=\frac{1}{r^2{\sin}\,\theta}\left|\begin{matrix}\hat{r} & r\,\hat{\theta} & r\,{\sin}\,\theta\,\hat{\varphi}  \\& & \\\frac{\partial}{\partial r} & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial \varphi}\\ & & \\E_r & rE_\theta & r{\sin}\,\theta\, E_\varphi\end{matrix}\right|=(0, 0, 0)

to find the expression for the potential function associated:

\vec E=\vec \nabla . V, \Delta V= V_b-V_a=-\int _c \vec E.d\vec l=-\int _c E\^r.dr\^r=-\int _c Edr=\int \limits^a_b \frac{Q}{4\pi \epsilon _0 r^2} dr= \frac{Q}{4\pi \epsilon _0}.(\frac{1}{r}|^b_a)= \frac{Q}{4\pi \epsilon _0}.(\frac{1}{b}-\frac{1}{a})

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Answer:

B

Explanation:

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