Answer:
The following query is used to display TripName. Reservationld, FirstName. LastName and TotalCost of trip by adding the trip price plus other fees and multiplying the result by the number of persons which have number of persons >4.
Query:
SELECT ReservationlD, Trip.TripName. Customer.LastName. Customer.FirstName. (TripPrice+OtherFees) 'NumPersons as TotalCost FROM Reservation, Trip, Customer WHERE NumPersons>4 AND Reservation.TriplD=Trip.TriplD AND
Customer. CustomerNum=Reservation.CustomerNum:
Explanation:
- Select clause is used to retrieve data from specified database table or relation and returns the data in the form of table.
- ReservationID. Trip.TripName. Customer.LastName. Customer.FirstName are the column name of table.
- (TripPrice+OtherFees) 'NumPersons will calculate the total cost of the Trip and stored it into TotalCost column.
- As clause is used to give new name TotalCost to resultant column.
- FROM clause specifies one or more table from where records to be retrieved. o Reservation. Trip and Customer are the table name.
- WHERE clause is used in SQL query to retrieve only those records that satisfy the specified condition
Answer: B: 20-degree incline
Explanation:
A tractor user should avoid slopes of more than 20 degrees in order to avoid rollovers
Answer:
Answer with Explanation is in the following attachments.
Explanation:
Explanation:
Instantaneous center:
It is the center about a body moves in planer motion.The velocity of Instantaneous center is zero and Instantaneous center can be lie out side or inside the body.About this center every particle of a body rotates.
From the diagram
Where these two lines will cut then it will the I-Center.Point A and B is moving perpendicular to the point I.
If we take three link link1,link2 and link3 then I center of these three link will be in one straight line It means that they will be co-linear.
Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
