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ratelena [41]
2 years ago
13

List two ways you can make an informal survey

Engineering
2 answers:
solniwko [45]2 years ago
8 0

The two ways you can use to make an informal survey are:

  • make field observations
  • interview people using informal unstructured techniques

<h3>What are informal surveys?</h3>

In informal surveys can be regarded as a type of survey that can be made by the researcher by going to the field themselves and this can be done by using different methods or ways.

For instance, the researcher can go out to interview people that can give the data that is needed about the research such as informally asking them questions,  unstructured techniques can also be used to solve critical issues.

learn more about survey at: brainly.com/question/6947486

#SPJ9

nlexa [21]2 years ago
3 0

The best informal research methods include asking quality questions, drawing on prior experience and knowledge, using guesses and hunches, having conversations, conducting surveys, reading documents, searching on the internet, running mini-experiments and doing a trial run.

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siniylev [52]

Answer:

I do

Explanation:

4 0
3 years ago
Read 2 more answers
The substance called olivine may have any composition between Mg2SiO4 and Fe2SiO4, i.e. the Mg atoms can be replaced by Fe atoms
Ipatiy [6.2K]

Answer:

The answer is "0.147 nm and  99.63 mol %"

Explanation:

In point (a):

\to nk1 = 062

\to \text{Bragg angle} \theta =37.21^{\circ}

\to \text{diffraction angle} 2 \theta = 74.42^{\circ}

\to \lambda = 0.1790 nm

find:

d(062)=?

formula:

\to nx = 2d \sin  \theta

\to  d(062) = \frac{1 \times 0.1790^{\circ}}{2 \times \sin 37.21^{\circ}}\\

               = \frac{0.1790^{\circ}}{2 \times 0.604738126}\\\\= \frac{0.29599589}{2}\\\\= 0.147 \\

In point (b):

\to Mg_2SiO_4\longleftrightarrow  Fe_2SiO_4

d= 0.14774  \ \ \ \ \ olivine = 0.147 \ \ \ \  \ 0.15153

formula:

\to d=\frac{a}{\sqrt{n^2+k^2+i^2}}\\

that's why the composition value equal to 99.63 %

3 0
3 years ago
1. Technician A says an automotive computer can scan its input and output circuits to detect incorrect voltage problems. Technic
Marta_Voda [28]
B is the correct answer
4 0
3 years ago
A gas cylinder is connected to a manometer that contains water. The other end of the manometer is open to the atmosphere, which
horrorfan [7]

Answer: the absolute static pressure in the gas cylinder is 82.23596 kPa

Explanation:

Given that;

patm = 79 kPa, h = 13 in of H₂O,

A sketch of the problem is uploaded along this answer.

Now

pA = patm + 13 in of H₂O ( h × density × g )

pA= 79 + (13 × 0.0254 × 9.8 × 1000/1000)

pA = 82.23596 kPa

the absolute static pressure in the gas cylinder is 82.23596 kPa

4 0
4 years ago
In a 1D compression test with double drainage, the pore pressure readings are practically zero after 8 minutes for a clay sample
frosja888 [35]

Answer:

The duration of the consolidation process for the same clay is 32 min

Explanation:

for clay 1:

t1=0

H1=thickness=2 cm

for the clay 2:

t2=?

H2=2 cm

The time factor is equal to:

T=(\frac{Cv}{d^{2} })t

where Cv is the coefficient of consolidation

(\frac{Cvt}{d^{2} })_{1}=  (\frac{Cvt}{d^{2} })_{2}

if Cv is constant, we have:

(\frac{t1}{(\frac{H1}{2}) ^{2} })_{1}=(\frac{t2}{H2^{2} })_{2}\\\frac{0}{(\frac{2}{2})^{2})  }=\frac{t2}{2^{2} }

Clearing t2:

t2=32 min

3 0
3 years ago
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