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labwork [276]
3 years ago
11

A 60.0 kg person walks from the ground to the roof of a 74.8 m tall building.how much potential energy doed the person have at t

he top?

Physics
1 answer:
faust18 [17]3 years ago
5 0
So first, we multiply mass by gravity by height, which is 60 * 9.8 * 74.8 = <span>43747.2

So the answer is: </span><span>43747.2

Hope this helped! c:</span>

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. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *
SpyIntel [72]

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

  • <em>gravity due to its weight</em>
  • <em>downward force due its acceleration</em>

<em />

The upward force on the indoor skydiver include the following;

  • <em>lift force</em>
  • <em>air resistance</em>

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

Learn more here:brainly.com/question/8947470

7 0
3 years ago
Which of the following is NOT a characteristic of vibrations?
Ivanshal [37]

Answer:

answer is (c) density is not a characteristics of vibration.

hope it is right answer for it!!

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3 years ago
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Anyone need a girl huh
Bess [88]

Answer:

no no no no

Explanation:

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3 years ago
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Describe what a convection current is in how it was material than the earth
Leona [35]
The movement of fluid as a result of differential heating or convection. Earth convection currents refer to the motion of molten rock in the mantle as radioactive decay heats up magma, causing it to rise and driving the global scale flow of magma.
3 0
3 years ago
To determine athletes body fat, there are weighed first in air and then again while they are completely underwater. It is found
rodikova [14]

Answer:

1065 Kgm-3

Explanation:

We can determine the relative density of the athlete from the formula;

Relative density of athlete = weight of athlete in air/upthrust on athlete

Since weight of athlete in air= 690 N

Weight of athlete in water = 42 N

Upthrust on athlete= weight in air - weight in water

Upthrust on athlete= 690 N - 42 N = 648 N

Relative density of athlete= 690 N / 648 N

Relative density of athlete= 1.065

Therefore, average density of the athlete= relative density × density of water = 1.065 × 1000 Kgm-3 = 1065 Kgm-3

4 0
4 years ago
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