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MrRissso [65]
3 years ago
11

Paco's age divided by 3 is equal to 4. Let p represent Paco's age and write an equation to model the situation. Then solve the e

quation to find Paco's age.
Mathematics
1 answer:
Zielflug [23.3K]3 years ago
4 0
An equation could be: p/3=4
To solve this equation: p/3*3/1=4*3/1
                                   : p=12
                                   : Paco is 12 years old--you are using what is called "Inverse Operation"!!!
(otherwise you could multiply 3*4 to get 12 by reversing operations)
I hope this helped you!
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3
ser-zykov [4K]

Answer: D. Subtracting 9 from each side

Step-by-step explanation:

Always start with numbers without variables first before doing anything with x. And make sure one side must not equal 0 unless you're doing polynomials.

5 0
3 years ago
What is the divisble test for 861?
Lynna [10]

Answer:

7 is the correct answer

8 0
3 years ago
Solve the equation: x+11=3
allochka39001 [22]

Answer:

\Large\boxed{x=-8}

Step-by-step explanation:

Isolate x on one side of the equation.

x+11-11=3-11 (Subtract 11 from both sides.)

3-11 (Solve & Simplify.)

3-11=-8

X=-8

\Large\boxed{\mathsf{\Rightarrow x=-8}}

So, the correct answer is x=-8.

7 0
3 years ago
Read 2 more answers
How do you factor x^2-5x+4 for the answer
tatiyna
Hi there!
In order to factor, start by knowing the variables for each term in the equation ax^2+bx+c
A=1
B=-5
C=4
(Based on the given equation)
In order to factor, we need to find two numbers that add to the b term (-5) but multiply to the c term (4)
-4*-1=4
-4+-1=-5
Therefore, the factored form would be y=(x-4)(x-1)

Hope this helps!
4 0
3 years ago
The telephone at the family store rang 156 times in the morning, a bunch during lunch, and 201 times that afternoon. During the
BARSIC [14]

<em>Data</em>

• Morning: 156 times

,

• Lunch: x times

,

• Afternoon: 201 times

,

• Whole day: 562 times

<em>Procedure</em>

To know how many times did it ring at lunch, we have to build a relation, in which we know that the addition of the times in the morning, lunch, and afternoon equal the times it rang the whole day:

156+x+201=562

Then, we have to solve for <em>x </em>considering that it represents the times it rang during the lunch.

156-156+x+201-201=562-156-201x=562-156-201x=205

Answer: It rang 205 times during the afternoon.

8 0
1 year ago
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