Answer:
SA= 12pl+B
Step-by-step explanation:
3! = 1 x 2 x 3 = 6
hope it helps
Answer:
The surface area is 
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
where
-----> the slant height
substitute the values
![SA=10^{2}+4[\frac{1}{2}(10)(14)]](https://tex.z-dn.net/?f=SA%3D10%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%2814%29%5D)
9514 1404 393
Answer:
y = 11.2 in
Step-by-step explanation:
The product of segment lengths to the near and far intersection points of the secant with the circle are the same for all secants from the same external point. Here, there are three, so we have the relations ...
9×9 = 5(5+y) = x(x+19)
Then the value of y can be found as ...
81/5 = 5+y
16.2 -5 = y = 11.2
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The value of x is a little trickier, as a quadratic is involved.
81 = x² +19x
81 + 90.25 = x² +19x +90.25 . . . . complete the square
171.25 = (x +9.5)²
x = √171.25 - 9.5 ≈ 3.58625...
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<em>Additional comment</em>
For the purpose here, the tangent can be considered to be a degenerate case of a secant in which the two points of intersection with the circle are the same point. For the purpose of this calculation, the length of the tangent is squared. (The distance to the points of intersection is the same.)
I find it easier to remember one rule, rather than a separate rule for tangents. With some imagination, the same rule can be applied when the "secants" meet <em>inside</em> the circle. In that case, they are called "chords".
We have shown the value for x because we suspect some versions of this question may ask for x instead of y. (Rounding may be required in that case.)
Answer:
43.17 ft/s
Step-by-step explanation:
Let the height of the wall is y.
distance of wall from light is 20 feet.
y = 20 tanθ .... (1)
time period, T = 3 second
Differentiate equation (1) with respect to t.
dy/dt = 20 x 2.16
dy/dt = 43.17 ft/s
