Answer:
C) Increases the pressure
Explanation:
Increasing the pressure might result in the change of temperature of the substance, which would change its state of matter.
Answer:
Explanation:
volume of heptane= mass / density
volume of heptane = 37. 8 / .684
= 55.26 mL
volume of water = 34.7 / 1
= 34.7 mL or cc.
If l₁ be the length of heptane layer in the graduated cylinder
volume = cross sectional area x length or height of layer
π r² x l where r is radius of bore of the cylinder , l is height of liquid inside cylinder .
for heptane
π r² x l₁ = 55.26
3.14 x 1.54² x l₁ = 55.26
l₁ = 7.42 cm
for water
π r² x l₂ = 34.7
3.14 x 1.54² x l₂ = 34.7
l₂ = 4.65 cm
Combined height = l₁ + l₂
= 7.42 + 4.65
= 12.07 cm .
For classification, the protists are divided into three groups: Animal-like protists, which are heterotrophs and have the ability to move. Plant-like protists, which are autotrophs that photosynthesize. Fungi-like protists, which are heterotrophs, and they have cells with cell walls and reproduce by forming spores.
Explanation:
The answer is
153.7
k
J
.
What you are asked to determine is the total energy required to go from ice to water, and then from water to vapor - the phase changes underwent by the water molecules.
In order to do this, you'll need to know:
Heat of fusion of water:
Δ
H
f
=
334
J
/
g
;
Heat of fusion vaporization of water:
Δ
H
v
=
2257
J
/
g
;
Specific heat of ice:
c
=
2.09
J
/
g
∘
C
;
Specific heat of water:
c
=
4.18
J
/
g
∘
C
;
Specific heat of steam:
c
=
2.09
J
/
g
∘
C
;
So, the following steps describe the overall process:
1. Determine the heat required to raise the temperature of the ice from
−
15.0
∘
C
to
0
∘
C
:
q
1
=
m
⋅
c
i
c
e
⋅
Δ
T
=
50.0
g
⋅
2.09
J
g
⋅
∘
C
⋅
(
0
∘
C
−
(
−
15
∘
C
)
)
=
1567.5
J
2. Determine the heat required to convert
0
∘
C
ice to
0
∘
C
water:
q
2
=
m
⋅
Δ
H
f
=
50.0
g
⋅
334
J
g
=
16700
J
3. Determine the heat required to go from water at
0
∘
C
to water at
100
∘
C
: