Based on the information given the percentage of the brown geese that are heterozygous is 48%.
Random sample = 250
Brown color = 210
Gray color = 250 - 210 = 40
First step is to calculate the proportion of a alleles in the population
Proportion (a alleles)=√40/250
Proportion (a alleles)= √0.16
Proportion (a alleles)= 0.4
Second step is to calculate the proportion of A alleles in the population
p(A) = 1 - 0.4
p(A)= 0.6
Third step is to calculate brown heterozygous percentage using this formula
Brown heterozygous percentage=2pq(Aa)
Let plug in the formula
Brown heterozygous percentage= 2 x 0.6 x 0.4
Brown heterozygous percentage= 0.48 ×100
Brown heterozygous percentage= 48%
Inconclusion the percentage of the brown geese that are heterozygous is 48%.
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Answer: peppers
Step-by-step explanation:
Peppers cost the greatest amount per pound
$1.62 (peppers) > $1.51 (turnips) > $1.48 (celery) > $1.26 (carrots)
a) For there to be a y-intercept of 3, when x=0, y=3.
- A. y=(0+1)(0-3)=-3
- B. y=0²-9=-9
- C. y=3(0)(0-3)=0
- D. y=(0+1)(0+3)=3.
So, the answer is D
b) For there to be roots of 0 and 3, there has to be factors of x and (x-3).
- The only choice that satisfies this is C
4 + 3 * (7 - 2)
4 + 3 * 5
4 + 15
19 <==
Answer:
a precent is a rate in which the first term is compared to 100.a unit rate is a rate in which the first term is compared to itself. so basically a and c
Step-by-step explanation: