Answer:
Explanation:
Oxygen molecules and Nitrogen molecules forms in a very similar way. The attraction between particles of oxygen is great due to its very high electronegativity value. Oxygen has a higher electronegative value compared to nitrogen.
Electronegativity of an atom is the relative tendency with which atoms of an element attracts valence electrons in a chemical bond. Valence electrons are used in forming chemical bonds. They can be transferred from one atom to the other or they can be shared.
Oxygen is the second most electronegative atom on the periodic table. To form a bond, it shares the valence electrons in order for its octet to be complete. Pull for the valence electrons between the contributing atoms is very strong due to their large electronegative values. This pull is stronger compared to that between nitrogen atoms.
Answer:
+2
Explanation:
The nitrate ion is a radical with an overall charge of -1. To get the oxidation number of lead, add up all the oxidation numbers and equate to zero. Therefore the oxidation state of lead is +2.
Metalloids:alloys of metallods are commonly used in discs like compact discs, CDs ,and DVDs .These materials change from glassy to crystalline with the application of heat which makes them useful as data storage media
Answer:
The mass of CO in 12,000 Liters of air is
.
Explanation:
The ppm is the amount of solute (in milligrams) present in one Liter of a solvent. It is also known as parts-per million.
To calculate the ppm of oxygen in sea water, we use the equation:

The ppm concentration of CO = 10 ppm
Mass of CO = m
Volume of air = 12,000 L


The mass of CO in 12,000 Liters of air is
.
Answer is: Te (tellurium).
During electron capture, iodine-123 f<span>orm the nearly-stable nuclide tellurium-123.
</span>In beta
plus decay (atomic number Z is decreased by one), a proton is converted to a neutron
and positron and an electron neutrino, so mass <span>number does not
change.
</span>Iodine-123 is a radioactive isotope of iodine used in nuclear medicine imaging.<span>
</span>