Polarity, cohesion, adhesion, surface tension, high specific heat, and evaporating cooling
In stars helium atoms are used with hydrogen atoms in order to produce energy.
Answer: A )
Answer:
Given: 42 g of N2
Solve for O2 mass that contains the same number of molecules to 42 g of N2.
Solve for the number of moles in 42 g of N2
1 mole of N2 = (14 * 2) g = 28 g so the number of moles in 42 g of N2 is equal to 42 g / 28 g per mole = 1.5 moles
Solve for mass of 1 mole of oxygen
1 mole of O2 = 16 g * 2 = 32 g per mole
Solve for the mass of 1.5 moles of oxygen
mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles
mass of 1.5 moles of O2 = 48 g
So 48 g of O2 contains the same number of molecules as 42 g of N2
The answer is B. Acid turns blue litmus paper to red
<u>Solution and Explanation:</u>
[La3+] = 0.1 M
<u>At the equilibrium:
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La(IO3)3 <----> La3+ + 3 IO3-
0.1 +s 3s
![\mathrm{Ksp}=[\mathrm{La} 3+][\mathrm{IO} 3-]^{\wedge} 3](https://tex.z-dn.net/?f=%5Cmathrm%7BKsp%7D%3D%5B%5Cmathrm%7BLa%7D%203%2B%5D%5B%5Cmathrm%7BIO%7D%203-%5D%5E%7B%5Cwedge%7D%203)
Since Ksp is small, s can be ignored as compared to the 0.1
The above shown expression thus becomes:
<u>Answer: 1.4*10^-4 M
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