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STatiana [176]
3 years ago
11

Following the procedure, a student recorded the initial volume of NaOH in his buret as 2.82 mL. He then titrated a 15.00 mL samp

le of 0.1027 M HCl until a persistent pale pink appeared. He recorded the final volume of NaOH in his buret as 17 mL. What is the concentration (M) of his NaOH solution?
Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

The concentration of this NaOH solution was 0.104 M

Explanation:

<u>Step 1:</u> Data given

Initial volume of NaOH = 2.82 mL = 0.00282 L

The sample is titrated with 15.00 mL of 0.1027 M HCl

Final volume NaOH = 17 mL = 0.017 L

<u>Step 2:</u>  Calculate change in volumes

17 mL - 2.82 mL = 14.18 mL = 0.01418 L

<u>Step 3: </u>Calculate the concentration of the NaOH

C1*V1 = C2*V2

⇒ with C1 = the initial concentration = TO BE DETERMINED

⇒ with V1 = the initial volume =  0.0148 L

⇒ with C2 = the final concentration = 0.1027

⇒ with V2 = the final volume = 0.015 L

C1 = (0.1027*0.015) /0.0148

C1 = 0.104 M

The concentration of this NaOH solution was 0.104 M

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2 years ago
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Answer:

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Explanation:

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3 years ago
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Answer:

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