Find the v first by using 3.14x0.22x2.16 div. 41g
Answer:
![\alpha=28.57\frac{rad}{s^2}](https://tex.z-dn.net/?f=%5Calpha%3D28.57%5Cfrac%7Brad%7D%7Bs%5E2%7D)
Explanation:
We use the following rotational kinematic equation to calculate the angular acceleration of the rod:
![\omega_f=\omega_0+\alpha t](https://tex.z-dn.net/?f=%5Comega_f%3D%5Comega_0%2B%5Calpha%20t)
Here
is the final angular speed,
is the initial angular speed and
is the angular acceleration. The rod starts rotating from rest (
):
![\alpha=\frac{\omega_f}{t}(1)](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7B%5Comega_f%7D%7Bt%7D%281%29)
Recall that the angular speed is defined in function of the tangential speed (v) and the radius (r) of the circular motion:
![w_f=\frac{v_f}{r}(2)](https://tex.z-dn.net/?f=w_f%3D%5Cfrac%7Bv_f%7D%7Br%7D%282%29)
In this case the radius is given by
. Replacing (2) in (1):
![\alpha=\frac{v_f}{rt}\\\alpha=\frac{20\frac{m}{s}}{(0.1m)7s}\\\alpha=28.57\frac{rad}{s^2}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7Bv_f%7D%7Brt%7D%5C%5C%5Calpha%3D%5Cfrac%7B20%5Cfrac%7Bm%7D%7Bs%7D%7D%7B%280.1m%297s%7D%5C%5C%5Calpha%3D28.57%5Cfrac%7Brad%7D%7Bs%5E2%7D)
- Energy from the Sun that reaches the Earth
HOPE IT HELPS U!!!
There is no work because there is no displacement
answer: 0