The equation most often associated with Newton's Second Law of Motion is

Chemistry

2 answers:

nignag [31]2 years ago

7 0

Answer:

F = ma or Force = mass x acceleration.

Explanation:

Newtons second law is about the force put onto an object. To find this you would use the formula:

Force is equal to mass times acceleration (F=ma)

Jet001 [13]2 years ago

7 0

Answer : The equation most often associated with Newton's Second Law of Motion is, $a=\frac{F}{m}$

Explanation:

Newton's second law : It is defined as the acceleration of an object is directly proportional to the amount of force applied to it and it is inversely proportional to the mass of an object.

The equation used for Newton's Second Law of Motion is:

$a=\frac{F}{m}$

where,

a = acceleration of an object

F = force applied on object

m = mass of an object

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Dissolution of KOH, ΔHsoln:

swat32

Using Hess's law we found:

1) By adding reaction 10.2 with the reverse of reaction 10.1 we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) ΔH (10.3)

2) The ΔHsoln must be subtracted from ΔHneut to get the total change in enthalpy (ΔH).

The reactions of dissolution (10.1) and neutralization (10.2) are:

KOH(s) → KOH(aq) ΔHsoln (10.1)

KOH(s) + HCl(aq) → H₂O(l) + KCl(aq) ΔHneut (10.2)

1) According to Hess's law, the total change in enthalpy of a reaction resulting from differents changes in various reactions can be calculated as the sum of all the enthalpies of all those reactions.

Hence, to get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

We need to add reaction 10.2 to the reverse of reaction 10.1

KOH(s) + HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq) + KOH(s)

Canceling the KOH(s) from both sides, we get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq) (10.3)

2) The change in enthalpy for reaction 10.3 can be calculated as the sum of the enthalpies ΔHsoln and ΔHneut:

$\Delta H = \Delta H_{soln} + \Delta H_{neut}$