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dsp73
3 years ago
12

The equation most often associated with Newton's Second Law of Motion is

Chemistry
2 answers:
nignag [31]3 years ago
7 0

Answer:

F = ma or Force = mass x acceleration.

Explanation:

Newtons second law is about the force put onto an object. To find this you would use the formula:

Force is equal to mass times acceleration (F=ma)

Jet001 [13]3 years ago
7 0

Answer : The equation most often associated with Newton's Second Law of Motion is, a=\frac{F}{m}

Explanation:

Newton's second law : It is defined as the acceleration of an object is directly proportional to the amount of force applied to it and it is inversely proportional to the mass of an object.

The equation used for Newton's Second Law of Motion is:

a=\frac{F}{m}

where,

a = acceleration of an object

F = force applied on object

m = mass of an object

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Which formula is an empirical formula?
poizon [28]
<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. NH_{3}

<h2>Why?</h2>

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

MolecularFormula=n(EmpiricalFormula)

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. N_{2}O_{4}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

N_{2}O_{4}=2(NO_{2})

B. NH_{3}

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. C_{3}H_{6}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

C_{3}H_{6}=3(CH_{2})

D. P_{4}O_{10}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

P_{4}O_{10}=2(P_{2}O_{5})

Hence, the empirical formula is the option B. NH_{3}

Have a nice day!

6 0
3 years ago
Read 2 more answers
60 kg of fuel was completely burnt for an experiment. The amount of heat energy was found to be 180000KJ. Calculate calorific va
FrozenT [24]

Answer:

3000 kJ/kg

Explanation:

The calorific value of a substance is the amount of heat produced per unit mass by the combustion of the substance.

It is given by:

C=\frac{Q}{m}

where

Q is the amount of heat released

m is the mass of the fuel

In this problem, we have:

m = 60 kg is the mass of fuel

Q=180,000 kJ is the amount of heat released

Therefore, the calorific value of the fuel is:

C=\frac{180,000}{60}=3000 kJ/kg

6 0
3 years ago
Free 100 for the boys​
Drupady [299]
Ok thanks wkwksnmenenenenenenwnwnnwnwnwnw
6 0
3 years ago
Read 2 more answers
What tool do you use to measure a rectangle?
pashok25 [27]

Answer:

Ruler

Explanation:

3 0
2 years ago
Read 2 more answers
how many kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution?
Lena [83]

Answer: The kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution is 3 kg.

Explanation:

According to the ratio and proportion:

C_1m_1=C_2m_2

where,

C_1 = concentration of ist solution = 25%

m_1 = mass of ist solution = 8 kg

C_2 = concentration of second solution = 40%

m_2 = mass of second solution = ? kg

25\times 8=40\times m_2

m_2=5kg

Thus the final solution must have a mass of 5 kg , i.e (8-5)= 3 kg of mass must be evaporated.

Therefore, the mass that must be evaporated from 8kg of a 25% salt solution to produce 40% salt solution is 3 kg.

6 0
3 years ago
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