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Kitty [74]
3 years ago
10

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate t

he amount of Ga ( s ) that can be deposited from a Ga ( III ) solution using a current of 0.710 A that flows for 70.0 min .
Chemistry
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

0.72g of gallium

Explanation:

Equation of the reduction reaction:

Ga^3+(aq) +3e --------> Ga(s)

If it takes 3F coulumbs of electricity to deposit 70g of gallium (relative atomic mass of gallium)

Then (0.710 × 70×60) coulombs of electricity will deposit (0.710 × 70×60) × 70/3F

But F = 96500C or 1Faraday

Therefore:

(0.710 × 70×60) × 70/3×96500

Mass of gallium deposited= 0.72g of gallium

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Which of the following is evidence of a chemical change?
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As a form of energy, light has specific properties such as color and brightness. Some properties can only be seen with special t
Sergeu [11.5K]

Answer:

D. As white light passes through a prism , it bends and separates into different colors

Explanation:

When light enters a prism, it experiences a phenomenon called 'refraction'.

Refraction occurs when light crosses the interface between two mediums with different optical density; when this happens, the light bends and also changes speed.

The angle at which the ray of light is refracted into the second medium depends on the optical density of the two mediums, but also on the wavelength of the light.

In particular, longer wavelengths (red color) are refracted the least, while shorter wavelengths (violet color) are refracted the most.

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So, the correct answer is

D. As white light passes through a prism , it bends and separates into different colors

5 0
3 years ago
an unknown amount of mercury (ii) oxide was decomposed in the lab. mercury metal was formed and 4.50 l of oxygen gas was release
Assoli18 [71]

The initial weight of mercury oxide in the sample was 59.1 g HgO.

<h3>Steps</h3>

chemical reaction

2HgO ⟶ 2Hg + O₂

the moles of O₂

pV = nRT

n = (pV)/(RT)

Data:

p = 0.970 atm

V = 4.50 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 390.0 K

Calculation:

n = (0.970 × 4.500)/(0.082 06 × 390.0)

n = 0.1364 mol O₂

the moles of HgO

The molar ratio is 1 mol O₂/2 mol HgO.

Moles of HgO = 0.1364 mol O₂ × (2 mol Hg/1 mol O₂)

Moles of HgO = 0.2728 mol HgO

the mass of HgO

Mass of HgO = 0.2728 mol HgO × (216.59 g HgO/1 mol HgO)

Mass of HgO = 59.1 g HgO

<h3>What is the name of HgO?</h3>

For the creation of various organic mercury compounds and specific inorganic mercury salts, mercury(II) oxide, or HgO, serves as a source of elemental mercury.

This red or yellow crystalline substance is also utilised in mercury batteries and zinc-mercuric oxide electric cells as an electrode (combined with graphite).

<h3>What is the purpose of mercury oxide?</h3>

Mercuric oxide is a colourless, crystalline powder that ranges from yellow to orange-yellow.

It serves as a seed protectant, a pigment, a preservative, and an ingredient in alkaline batteries and cosmetics.

<h3>Is there a combination of mercury oxide?</h3>
  • The powder form of mercury oxide is dark black or dark brown.
  • An intimate blend of metallic mercury and mercuric oxide rather than a genuine compound.

learn more about mercury oxide here

brainly.com/question/3235037

#SPJ4

4 0
2 years ago
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