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solong [7]
3 years ago
15

In an inertial frame of reference, a series of experiments is conducted. In each experiment, two or three forces are applied to

an object. The magnitudes of these forces are given. No other forces are acting on the object. In which cases may the object possibly move at a constant velocity of 256m/s
Physics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Explanation:

1.2 \mathrm{N} ; 2 \mathrm{N}

2.200 \mathrm{N} ; 200 \mathrm{N}

4.2 \mathrm{N} ; 2 \mathrm{N} ; 4 \mathrm{N}

5.2 \mathrm{N} ; 2 \mathrm{N} ; 2 \mathrm{N}

6.2 \mathrm{N} ; 2 \mathrm{N} ; 3 \mathrm{N}

8.200 \mathrm{N} ; 200 \mathrm{N} ; 5 \mathrm{N}

In only the above cases (i.e 1,2,4,5,6,8 ) the object possibly moves at a constant velocity of 256 \mathrm{m} / \mathrm{s}

You should have noticed that the sets of forces applied to the object are the same asthe ones in the prevous question. Newton's 1st law (and the 2nd law, too) makes nodistinction between the state of re st and the state of moving at a constant velocity(even a high velocity).

In both cases, the net force applied to the object must equal zero.

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When a honeybee flies through the air, it develops a charge of +20 pC . Part A How many electrons did it lose in the process of
Yuri [45]

Answer:

1.3 × 10⁸ e⁻

Explanation:

When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:

20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻

1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:

2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻

7 0
4 years ago
In a regression analysis, if sse = 200 and ssr = 300, then the coefficient of determination is:_________
Nataliya [291]

0.600

In a regression analysis, if sse = 200 and ssr = 300, then the coefficient of determination is: <u>0.600</u>

<u></u>

1. You have that the data set having SSR=300 and SSE=200

2. Therefore you have the coefficient of determination is:

r²=SSR/SSTO

SSTO=SSR+SSE

3. Then, when you substitute the values, you obtain:

SSTO=200+300

SSTO=500

r²=300/500

4. So, you have that the result is:

r²=0.6

As a result, as you can see, the solution to the previous exercise is that the coefficient of determination is 0.6

<h3>What exactly is the connection between SST, SSR, and SSE?</h3>
  • The difference between SST and SSR is the amount of Y's variability that is still unaccounted for after using the regression model, also known as the sum of squared errors (SSE). Sum of squares of residual can be used to directly calculate SSE.

To learn more about regression analysis visit:

brainly.com/question/12213669

#SPJ4

8 0
2 years ago
A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.90 m/s2 . At 20.0s after blastoff, t
Brilliant_brown [7]

Answer:

A) 580m

B) 0 m/s

C) 9.8m/s^2

D) downward

E) 10.87s

F) 106.62 m/s

Explanation:

A) The distance traveled by the rocket is calculated by using the following expression:

y=\frac{1}{2}at^2

a: acceleration of the rocket = 2.90 m/s^2

t: time of the flight = 20.0 s

y=\frac{1}{2}(2.90\frac{m}{s^2})(20.0s)^2=580m

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.

C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2

D) The acceleration points downward

E) The time the rocket takes to return to the ground is given by:

t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(580m)}{9.8m/s^2}}=10.87s

10.87 seconds

F) The velocity just before the rocket arrives to the ground is:

v=\sqrt{2gy}=\sqrt{2(9.8m/s ^2)(580m)}=106.62\frac{m}{s}

6 0
3 years ago
What is the name of the quantity represented by the symbol ω?
Strike441 [17]

Answer:

angular velocity

Explanation:

In physics the quantity represented by \omega is the <u>angular velocity, </u>the units of the angular velocity are radians/second.

This is a quantity that represents the speed when the movement of an object follows a circular path.

Mathematically defined as follows:

\omega = \frac{2\pi}{T}

Where T is the period, the time it takes to complete a lap.

8 0
3 years ago
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boyakko [2]
It’s mass is 100 kg, because if you divide both numbers, you get 100
6 0
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