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belka [17]
3 years ago
8

) Calculate the molarity of a solution prepared by dissolving 117 g of sodium chloride (NaCl) in enough water to make 2.7 liters

of solution.
Chemistry
1 answer:
Andrej [43]3 years ago
8 0
The Molarity of the solution is given by:
Molarity =  \frac{moles-of-solute}{liters-of-solution} --- (A)

But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.

Molecular weight of NaCl = 58.44 grams/mole.

So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl

Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre

The correct answer is: 0.741 moles/litre = Molarity
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Atoms, and chemical make up

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5 0
2 years ago
Equal volumes of H2 and o2 are placed in a balloon and then ignited. Assuming that the reaction goes to completion, which gas wi
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3 years ago
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Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the
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Answer is: mass of unused sulfur is 5.87 grams.

Balanced chemical reaction: C + 2S → CS₂.

m(C) = 12.0 g; mass of carbon.

m(S) = 70.0 g; mass of sulfur.

n(C) = m(C) ÷ M(C).

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n(C) = 1 mol; amount of substance.

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n(S) = 2.183 mol.

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n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

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