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belka [17]
3 years ago
8

) Calculate the molarity of a solution prepared by dissolving 117 g of sodium chloride (NaCl) in enough water to make 2.7 liters

of solution.
Chemistry
1 answer:
Andrej [43]3 years ago
8 0
The Molarity of the solution is given by:
Molarity =  \frac{moles-of-solute}{liters-of-solution} --- (A)

But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.

Molecular weight of NaCl = 58.44 grams/mole.

So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl

Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre

The correct answer is: 0.741 moles/litre = Molarity
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A solution has a poh of 7. 1 at 10∘c. what is the ph of the solution given that kw=2. 93×10−15 at this temperature? remember to
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A solution has a pOH of 7. 1 at 10∘c. Then the pH of the solution given that kw=2. 93×10−15 at this temperature is 7.4 .

It is given that,

pOH of solution = 7.1

Kw =2.93×10^(-15)

Firstly, we will calculate the value of pKw

The expression which we used to calculate the pKw is,

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learn more about pH value:

brainly.com/question/12942138

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Search...
denis23 [38]
Answer: The answer is the second one
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3 years ago
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