Answer:
2.11 g hydrobromic acid (correct to 3SF)
Explanation:
Molecular formula of hydrobromic acid = C2H5BrO2
mass of C2H5BrO2 = 140.96g
Beginning with what we're given, 9.03*10^21 we then make a conversion by using Avegadro's number which is 6.02*10^23 per mole (Oct. 23 at 6:02 am is national mole day :) Then, we need to convert out of moles, 140.96g hydrombromic acid per mole.
It looks like this:
9.03*10^21 molecules • (1 mol C2H5BrO2 / 6.02*10^23 molecules) • (140g C2H5BrO2 / 1 mol) = 2.1144 g C2H5BrO2
We have been given the condition that carbon makes up 35%
of the mass of the substance and the rest is made up of oxygen. With this, it
can be concluded that 65% of the substance is made up of oxygen. If we let x be
the mass of oxygen in the substance, the operation that would best represent
the scenario is,
<span> x = (0.65)(5.5 g)</span>
<span> <em> </em><span><em>x =
3.575 g</em></span></span>
Answer:
23.0 s⁻¹ is rate constant
Explanation:
Using the Arrhenius equation:
k = A * e^(-Ea/RT)
Where k is rate constant
A is frequency factor (1.5x10¹¹s⁻¹)
Ea is activation energy = 55800J/mol
R is gas constant (8.314J/molK)
And T is absolute temperature (24°C + 273 = 297K)
Replacing:
k = 1.5x10¹¹s⁻¹ * e^(-55800J/mol/8.314J/molK*297K)
k = 1.5x10¹¹s⁻¹ * 1.53x10⁻¹⁰
k = 23.0 s⁻¹ is rate constant i hope this helpsss
Explanation:
