The heat will flow from Cu to Fe because Cu has higher temperature and has lower peak value .
Given ,
two aircraft rivets , one iron and the other copper , are placed in a calorimeter .
the initial temp of the calorimeter is 20 degC .
mass of iron = 30 g
initial temp of iron = 0 degC
Mass of copper = 20 g
initial temp of copper = 100 degC
Here copper has higher temp ,thus heat flow from Cu to Fe .
<h3>
What is heat flow ?</h3>
Heat flow is the movement of heat from higher temperature to lower temperature .
<h3>What is calorimeter ?</h3>
It is an object used for measuring the heat flow , heat capacity of a chemical reaction as well as the physical changes .
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Answer:
A.
Explanation:
Using the ideal gas equation, we can calculate the number of moles present. I.e
PV = nRT
Since all the parameters are equal for both gases, we can simply deduce that both has the same number of moles of gases.
The relationship between the mass of each sample and the number of moles can be seen in the relation below :
mass in grammes = molar mass in g/mol × number of moles.
Now , we have established that both have the same number of moles. For them to have the same mass, they must have the same molar masses which is not possible.
Hence option A is wrong
Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.
Hank's Garage has an air compressor with a holding tank that contains a volume of 200L (V₁) of compressed air at a pressure of 5200 torr (P₁).
One day a hose ruptured and all the compressed air was released. The final pressure was the atmospheric pressure (1 atm = 760 torr) (P₂).
We can calculate the new volume (V₂) in these conditions using Boyle's law, which states there is an inverse relationship between the volume and the pressure of an ideal gas.
Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.
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Answer:
n Al= 10/27( mol)- >n Al2O 3 =5/27(mol)
Explanation: