The First 2 statements stated above were false whereas the third one is a true statement.
Explanation:
- The viscosity of bitumen is about 100 times greater than the viscosity of water - False
Reason - The viscosity of bitumen is about not 100 times greater than the viscosity of water, it is actually 100, 000 times greater.
- Oil from oil sand deposits is only obtained by first heating the sands at high temperatures is False.
Reason- Oil from oil sand deposits is not obtained by first heating the sands at high temperatures but by using steams
- Oil sands contain sand, water, and light crude oil is true.
Benzene is more volatile.
Electrons are electrochemically negatively charged particles that move random around the nucleus. They have a relatively small mass compared to Protons and Neutrons. They are found in electron clouds that surround the nucleus and their movement and properties provide for the bonding characteristics of each atom.
Answer:
The chemistry will need 2*10⁶ moles of antimony trifluoride.
Explanation:
The balanced reaction is:
3 CCl₄ (g) + 2 SbF₃ (s) → 3 CCl₂F₂(g) + 2 SbCl₃ (s)
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- CCl₄: 3 moles
- SbF₃: 2 moles
- CCl₂F₂: 3 moles
- SbCl₃: 2 moles
You can apply the following rule of three: if by reaction stoichiometry 3 moles of freon are produced by 2 moles of antimony trifluoride, 3*10⁶ moles of Freon are produced from how many moles of antimony trifluoride?

moles of antimony trifluoride= 2*10⁶
<u><em>The chemistry will need 2*10⁶ moles of antimony trifluoride.</em></u>
A 25.00 ml sample of hydrochloric acid solution, HCl, is titrated with 0.0512 m NaOH solution. the volume of NaOH solution required is 21.68 ml then the molarity of the HCl solution is 0.044 M .
Calculation ,
Formula used :
...( i )
Where M is the molarity or concentration and V is the volume in ml .
concentration of hydrochloric acid solution (
) = ?
concentration of NaOH (
) = 0.0512 M
volume of hydrochloric acid solution (
) = 25.00 ml
volume of NaOH (
) = 21.68 ml
Putting the value of concentration , volume of both in equation ( i ) we get .
× 25.00 ml = 0.0512 × 21.68 ml
= 0.0512 × 21.68 ml / 25.00 ml= 0.044 M
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