<span>As the pressure is increased the solubility of the sugar and carbon dioxide is increased. The pressure of combination leaves little to no separation. There would be no discernable difference between the ingredients used to make the saturated solution.</span>
Anytime an atom shares or transfers electrons a bond is formed, sharing= covalent and transfer= ionic
<h2>Step 1 : Identify the given </h2>
Volume = 250mL
Density = 1.19 g/ML
<h2>Step 2 . Calculate the mass of HCL </h2>
Density = mass/volume
∴Mass = Density * Volume
= 1.19g/mL* 250mL
= 297,5g
<h2>Step 3 : Calculate the total mass of the solution, given that concentration HCL is 38% </h2>
Mass of the total solution can be calculated by the following :
38% = Mc /297.5 * 100
Mc = 38/100 *297.5
= 113.05grams
• Finally, this means that mass of the total solution of 0.125M HCL i,s 113grams, ,you would use this mass to prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0%
2.B. Describe the difference between a reaction that occurs spontaneously and one that does not. Spontaneous chemical reactions release energy and use that energy to power itself; non-spontaneous chemical reactions need to absorb energy, which they can't absorb their own energy that they don't even have.
Answer:
70 mL of 5% HCl and 30 mL of 15% HCl
Explanation:
We will designate x to be the fraction of the final solution that is composed of 5% HCl, and y to be the fraction of the final solution that is composed of 15% HCl. Since the percentage of the final solution is 8%, we can write the following expression:
5x + 15y = 8
Since x and y are fractions of a total, they must equal one:
x + y = 1
This is a system of two equations with two unknowns. We will proceed to solve for x. First, an expression for y is found:
y = 1 - x
This expression is substituted into the first equation and we solve for x.
5x + 15(1 - x) = 8
5x+ 15 - 15x = 8
-10x = -7
x = 7/10 = 0.7
We then calculate the value of y:
y = 1 - x = 1 - 0.7 = 0.3
Thus 0.7 of the 100 mL will be the 5% HCl solution, so the volume of 5% HCl we need is:
(100 mL)(0.7) = 70 mL
Similarly, the volume of 15% HCl we need is:
(100 mL)(0.3) = 30 mL
