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3 years ago

BRAINLIEST!!!!!

Physics

1 answer:

Serggg [28]3 years ago

5 0

Answer:

A., an action which causes movement and an opposite reaction

Explanation:

I don't really know how to explain it, but this helped hopefully! :) Have a bless day

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A 4 kg bird is flying with a velocity of 4 m/s. What is its kinetic energy?

Maslowich

32 kg m/s would be the kinetic energy.

3 0

2 years ago

A particle (m = 4.3 × 10^-28 kg) starting from rest, experiences an acceleration of 2.4 × 10^7 m/s^2 for 5.0 s. What is its de B

Novay_Z [31]

Answer:

Wavelength, $\lambda=1.28\times 10^{-14}\ m$

Explanation:

Given that,

Mass of the particle, $m=4.3\times 10^{-28}\ kg$

Acceleration of the particle, $a=2.4\times 10^7\ m/s^2$

Time, t = 5 s

It starts from rest, u = 0

The De Broglie wavelength is given by :

$\lambda=\dfrac{h}{mv}$

v = a × t

$\lambda=\dfrac{h}{mat}$

$\lambda=\dfrac{6.67\times 10^{-34}}{4.3\times 10^{-28}\times 2.4\times 10^7\times 5}$

$\lambda=1.28\times 10^{-14}\ m$

Hence, this is the required solution.

4 0

2 years ago

Two streams merge to form a river. One stream has a width of 8.4 m, depth of 3.5 m, and current speed of 2.2 m/s. The other stre

hoa [83]

Answer:

Explanation:

We shall solve this problem on the basis of pinciple that water is incompressible so volume of flow will be equal at every point .

rate of volume flow of one stream

= cross sectional area x velocity

= 8.4 x 3.5 x 2.2 = 64.68 m³ /s

rate of volume flow of other stream

= 6.6 x 3.6 x 2.7

= 64.15 m³ /s

rate of volume flow of rive , if d be its depth

= 11.2 x d x 2.8

= 31.36 d

volume flow of river = Total of volume flow rate of two streams

31.36 d = 64.15 + 64.68

31.36 d = 128.83

d = 4.10 m /s .

6 0

2 years ago

Which two atmospheric gases do not react with many substances?

ValentinkaMS [17]

Answer: C and B :)

This is the Apex answer.

4 0

3 years ago

Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250

m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = $\dfrac{\pi}{4}d^2$

v = Terminal velocity = $v=210\ m/s$

s = Displacement = 150 m

$a=\dfrac{v^2-u^2}{2s}$

Force is given by

F = ma

$F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622$

The drag coefficient is 0.363999909622 (ignoring negative sign)

4 0

3 years ago