Answer:
The correct answer is option b.
Explanation:

The ionic product of water : 
![K_w=[H^+][OH^-]](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5BOH%5E-%5D)
A pure water has equal concentration of hydrogen ions and hydroxide ions, hence neutral.
![K_w=[H^+][H^+]=[H^+]^2](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5BH%5E%2B%5D%3D%5BH%5E%2B%5D%5E2)
The ionic product of water at 283 K = 
![K_w=[H^+]^2](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5E2)
![0.29\times 10^{-14}=[H^+]^2](https://tex.z-dn.net/?f=0.29%5Ctimes%2010%5E%7B-14%7D%3D%5BH%5E%2B%5D%5E2)
![[H^+]=5.385\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D5.385%5Ctimes%2010%5E%7B-8%7D%20M)
The pH of the water at 283 k;
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
![=-\log[5.385\times 10^{-8} M]=7.26](https://tex.z-dn.net/?f=%3D-%5Clog%5B5.385%5Ctimes%2010%5E%7B-8%7D%20M%5D%3D7.26)
A pure water has equal concentration of hydrogen ions and hydroxide ions,So water will e neutral at this temperature also.
The correct answer is option b.
I hope this helped♡ I drew the realationship of variables
Answer:
Option F. 3moles
Explanation:
The equation for the reaction is given below:
2H2 + O2 —> 2H2O
from the equation,
2moles of H2 required 1mole of O2.
Therefore, 6moles of H2 will require = 6/2 = 3moles of O2
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