Explanation:
In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.
Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.
For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.
Answer:
um well
Explanation:
get ur paddles and start rowing by putting ur hands on the paddles, and then rowing them by putting the paddle up, and then back into the water.
Answer:3W
If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?
A) 2W
B) 3W
C) 4W
D) 6W
Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other is
W = k(+q)(+q)/ d
k is couloumb's constant
work done in moving 3 equal positive charges from infinity to a finite distance is given by
W₂=W₄=W₆=k(+q)(+q)/ d
Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d
= W + W + W = 3W
Answer: -1.27 m/s^2
Explanation:
a = - V^2 / 2x
a = -(25^2) / 2 x (246) = 1.27 m/ s^2
Therefore the linear acceleration of the wheel is - 1.27 m/s^2
