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kvv77 [185]
3 years ago
8

What is pitch related to?

Physics
1 answer:
Jlenok [28]3 years ago
7 0
Pitch is related to frequency
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Based on its location on the periodic table, which element is a metal?
goldfiish [28.3K]

Sodium (Na) is a Alkali metal so that's the answer

6 0
3 years ago
Read 2 more answers
1. Calculati greutatea unui sac cu 5 kg de cartofi într-o zonă in care acceleratia gravitatională
harkovskaia [24]

Answer:

the weight is 49.1 N

Explanation:

The computation of the weight is shown below:

As we know that

= 5kg of potatoes × gravitational acceleration

= 5kg of potatoes × 9.82 m/s

= 49.1 N

Hence, the weight is 49.1 N

We simply applied the above formula in order to determine the weight

6 0
3 years ago
A hole is punched at A in a plastic sheet by applying a 660-N force P to end D of lever CD, which is rigidly attached to the sol
olasank [31]

Answer:

hello your question lacks some data and required diagram

G = 77 GPa,  т all = 80 MPa

answer : required diameter = 252.65 * 10-^3 m

Explanation:

Given data :

force ( P )  = 660 -N force

displacement = 15 mm

G = 77 GPa

т all = 80 MPa

i) Determine the required diameter of shaft BC

considering the vertical displacement ( looking at handle DC from free body diagram )

D' = 0.3 sin∅  ,   where D = 0.015

hence ∅ = 2.8659°

calculate the torque acting at angle ∅  of  CD on the shaft BC

Torque = 660 * 0.3 cos∅

             = 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N

hello attached is the remaining part of the solution

4 0
3 years ago
In the deep ocean, a water wave with wavelength 95 m travels at 12 m/s. Suppose a small boat is at the crest of this wave, 1.2 m
dimaraw [331]

Answer:

the vertical position is 1.1971m

Explanation:

Recall that

y = 1.2 * cos (\frac{2*\pi * distance travelled}{wavelenght})

recall that v = \frac{distance}{time}

thus;  distance =  v* t

this implies that distance = 12 * 5.0

                                          =  60

therefore;  y = 1.2 cos \frac{2*3.142*60}{95}

                  y = 1.1971m

the

3 0
3 years ago
Calculate the force between two objects that have masses of 70 Kilograms and 2,000 kilograms separated by a distance of 1 meter
Hunter-Best [27]

9.3 x 10⁻⁶N

Explanation:

Given parameters:

Mass 1 = 70kg

Mass 2 = 2000kg

distance = 1m

Unknown:

force between them =  

Solution:

The force between the two masses will be a gravitational force of attraction.

  F = \frac{G m_{1}m_{2}  }{r^{2} }

 G is universal gravitation constant = 6.67430×10−¹¹ N⋅m²/kg²

 r is the distance between the two masses

Substituting the parameters:

 F = \frac{6.67 x 10^{-11} x 70 x 2000}{1^{2} } = 9.3 x 10⁻⁶N

 Learn more:

Universal gravitation constant   brainly.com/question/1724648

#learnwithBrainly

5 0
3 years ago
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