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3 years ago

1. how do scientists classify small objects in solar system

2 answers:

7 0

I believe the correct answer from the choices listed above is the last option. Scientists classify small objects in the solar system by its <span>size , shape , and composition. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>

polet [3.4K]3 years ago

6 0

Option D is the correct answer. Option C is incorrect cuz temperature is not constant in outer space which makes difficult for classification. So composition of objects matters. Hence D. Hope it helps.

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For those who think electric cars are sissy, Keio University in Japan has tested a 22-ft long prototype whose eight electric mot

Kruka [31]

Answer:

The percent of power extended against sea-level air drag is 50.15%

Explanation:

Length L is 22 ft, Power P is 590 hp,

Speed of air V = 175 mi/h. To convert to ft, we will multiply by 1.46

V = 175 × 1.46 = 255.5 ft

Frontal Area A is given as 23.5 ft

Coefficient of drag, Cd is 0.35

From text, Density of Air at sea level ρ = 0.00237 slug/ft³

The formula for calculating Drag Force F is

F = Cd × $\frac{1}{2}$ × ρAV²

Substitute the values above into the formula

F = 0.35 × $\frac{1}{2}$ × 0.00237 × 23.5 × 255.5²

= 0.35 × $\frac{1}{2}$ × 3635.78

= 636.26 lbf

But Power P = FV

Therefore we substitute for F and V to get P

P = 636.26 × 255.5

= 162564.43 ft.lbf/s

To convert to horsepower, we multiply by 0.00182 hp

= 162564.43 × 0.00182

= 295.87 hp

The percent of power extended against sea-level air drag is

= (295.87/590) × 100

= 50.15%

6 0

3 years ago

Read 2 more answers

What is the use of a hydrometer

kherson [118]

Answer:

A hydrometer is an instrument used to determine specific gravity

5 0

3 years ago

Read 2 more answers

Four objects are situated along the y axis as follows: a 2.02 kg object is at 3.03 m, a 2.92 kg object is at 2.43 m, a 2.53 kg o

levacccp [35]

Answer:

0.975 m

Explanation:

The center of mass y = ∑m₁y₁/∑m₁ where m₁ = the individual masses and y₁ = the y - coordinates of the individual masses

So,

y = (2.02 kg × 3.03 m + 2.92 kg × 2.43 m + 2.53 kg × 0 m + 4.02 kg × -0.501 m)/(2.02 kg + 2.92 kg + 2.53 kg + 4.02 kg)

y = (6.1206 kgm + 7.0956 kgm + 0 kgm - 2.01402 kgm)/11.49 kg

y = 11.20218 kgm/11.49 kg

y = 0.975 m

So, the y- component of the center of mass of these objects is 0.975 m

8 0

3 years ago

2. How can people know that they've learned?

photoshop1234 [79]

Answer: People know that they jap e learned by their mistakes or by someone ya being them something

4 0

3 years ago

A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m/s experiences a magnetic

Sunny_sXe [5.5K]

Answer:

Explanation:

let the charge is q. velocity, v = 24.7 m/s

magnetic force, F = 2.38 x 10^-4 N

Let the magnetic field is B.

Velocity, v' = 5.64 m/s

angle, θ = 21.2°

The force experienced by a charged particle placed in a magnetic field is given by

F = q x v x B x Sinθ

in first case

2.38 x 10^-4 = q x 24.7 x B x Sin 90 .... (1)

in second case

F = q x 5.64 x B x Sin 21.2° .... (2)

Divide equation (2) by equation (1), we get

$\frac{F}{2.38\times 10^{-4}}=\frac{5.64\times Sin 21.2}{24.7\times Sin 90}$

F = 1.97 x 10^-5 N

7 0

4 years ago