<u>Answer:</u> The actual yield of the carbon dioxide is 47.48 grams
<u>Explanation:</u>
For the given balanced equation:
To calculate the mass for given number of moles, we use the equation:
Theoretical moles of carbon dioxide = 1.30 moles
Molar mass of carbon dioxide = 44 g/mol
Putting values in above equation, we get:
To calculate the theoretical yield of carbon dioxide, we use the equation:
Theoretical yield of carbon dioxide = 57.2 g
Percentage yield of carbon dioxide = 83.0 %
Putting values in above equation, we get:
Hence, the actual yield of the carbon dioxide is 47.48 grams
Answer:
4.45 atm
Explanation:
Applying,
PV = P'V'............ Equation 1
Where P = Initial pressure of the container, V = Initial volume of the container, P' = Final pressure of the container, V' = Final volume of the container.
make P the subject of the equation
P = P'V'/V........... Equation 2
From the question,
Given: V = 55.2 L, P' = 8.53 atm, V' = 28.8 L
Substitute these values into equation 2
P = (8.53×28.8)/55.2
P = 4.45 atm
Answer:
Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution
Explanation:
As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.
When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.
This gas turn red litmus paper blue.
This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).
If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.
