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inn [45]
3 years ago
9

Help!! I have no idea what to do!

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
5 0
I dunno............................................

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Never heard of this!!
Ksivusya [100]

Answer:

See explanation

Explanation:

a) u= 60 m/s, v= 45 m/s, t = 7 secs

From;

v = u + at

a = v - u/t

a= 45 - 60/7

a = -2.14 m/s^2

b)

u = 200 m/s

v= 235 m/s

t = 30 secs

v = u + at

a = v-u/t

a = 235 - 200/30

a= 1.17 m/s^2

c)

i) Acceleration = 3 - 1/2-0 = 2/2  = 1 m/s^2

ii) The slope between 2 and 5 is zero because velocity was not changing with time.

iii) Within the time between 2 and 5 the speed remained at 3 m/s

iv) the slope between 5 and 8 is 2 - 3/8 - 5 = -1/3 = -0.33m/s^2

v) The negative slope means that velocity is decreasing with time(deceleration).

7 0
2 years ago
Why are many fossil remains left from the last ice age
Vaselesa [24]
<span>They follow mostly from pleistocene climate and topography, so are in general less tightly controlled by bedrock than others. Most terrestrial fossil remains are found either in ponds dating from the receding of previous glaciers or isolated teeth or bone fragments in glacial till. Some important faunas, however, are preserved in pleistocene caves.
i hope this answered your question.</span>
8 0
3 years ago
10. On the basis of the general solubility rules given
Crank
I think it’s c but I could be wrong
3 0
3 years ago
A patient needs to take 625 mg of ibuprofen twice daily. The pills in the bottle are each 250. mg. How many pills does the patie
WINSTONCH [101]
2 and a half
250 x 2 =500
250/2=125
and 125 is a half of 250
so your answer is
2 and a half
5 0
3 years ago
Read 2 more answers
A compound is 52.0% zinc 9.6% carbon and 38.4% oxygen. Calculate the empirical formula of the compound.
skad [1K]

Answer:

So a compound is 52% Zinc(Zn), 9.6% Carbon(C), and 38.4% Oxygen (O). Let’s first start off by assuming that we have 100 g of this compound. This means that we have 52 g of Zinc, 9.6 g of Carbon, and 38.4 g of Oxygen.Zinc = 65.38 g/molCarbon = 12 g/molOxygen = 16 g/molThis means we have:52 g of Zn(1 mol Zn/65.38 g of Zn) ≈0.8 mol of Zn.9.6 g of C(1 mol C/12 g of C) = 0.8 mol of C38.4 g of O(1 mol of O/16 g of O) = 2.4 mol of O.

Explanation:

What we want to do next is divide each element by the common factor of all of them, which is 0.8. In most cases, you divide each element by the element with the least amount of moles. After we divide each by 0.8, you’ll notice you have 1 Zn, 1 C, and 3 O. This gives you the empirical formula of ZnCO3, or Zinc Carbonate.

6 0
2 years ago
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