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3 years ago

The mass of a single gold atom is 3.27×10-22 grams. how many gold atoms would there be in 236 milligrams of gold?

2 answers:

8 0

The amount of gold atoms could be calculated by dividing the total weight of the gold with the mass of a single gold atom. Just convert the given weight to grams then divide it with 3.27x10^-22 grams. The answer would be 7.22x10^20.

Arisa [49]3 years ago

3 0

Answer:

6.38*10²⁰ atoms of gold

Explanation:

236mg of gold = 236*10^-3g = 0.236g.

Now from the question,

1 atoms contains = 3.7*10^-22g.

X atoms will contain = 0.236g of gold.

Now we'll cross multiply and make x the subject of formula to find the amount of gold in 0.236g of gold.

X = (0.236 * 1) / 3.7*10^-22

X = 6.378*10^20 atoms

0.236g of gold contains 6.378*10^20 atoms of gold

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What are the disadvantages and advantages for electromagnetic spectrum

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Answer:

Advantages: In small quantities they help your body produce vitamin D.

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Explanation:

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3 years ago

A particle starts from rest and has an acceleration function 5 − 10t m/s2 . (a) What is the velocity function? (b) What is the p

frez [133]

Explanation:

It is given that,

A particle starts from rest and has an acceleration function as :

$a(t)=(5-10t)\ m/s^2$

(a) Since, $a=\dfrac{dv}{dt}$

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$dv=a.dt$

$v=\int(a.dt)$

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$v=5t-\dfrac{10t^2}{2}=5t-5t^2$

(b) $v=\dfrac{dx}{dt}$

x = position

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$x=\int (5t-5t^2)dt$

$x=\dfrac{5}{2}t^2-\dfrac{5}{3}t^3$

(c) Velocity function is given by :

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$5t-5t^2=0$

t = 1 seconds

So, at t = 1 second the velocity of the particle is zero.

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2 years ago

The period P of a pendulum depend on its length , mass as well as the acceleration due to gravity . Use dimensional analysis to

Savatey [412]

Explanation:

Period P has units of seconds (s).

Length has units of meters (m).

Mass has units of kilograms (kg).

Acceleration has units of meters per second squared (m/s²).

Dimensional analysis:

s = √(m / (m/s²))

Therefore:

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3 years ago

A loaded ore car has a mass of 950 kg. and rolls on rails ofnegligible friction. It starts from rest ans is pulled up a mineshaf

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(a) 10241 W

In this situation, the car is moving at constant speed: this means that its acceleration along the direction parallel to the slope is zero, and so the net force along this direction is also zero.

The equation of the forces along the parallel direction is:

$F - mg sin \theta = 0$

where

F is the force applied to pull the car

m = 950 kg is the mass of the car

$g=9.8 m/s^2$ is the acceleration of gravity

$\theta=30.0^{\circ}$ is the angle of the incline

Solving for F,

$F=mg sin \theta = (950)(9.8)(sin 30.0^{\circ})=4655 N$

Now we know that the car is moving at constant velocity of

v = 2.20 m/s

So we can find the power done by the motor during the constant speed phase as

$P=Fv = (4655)(2.20)=10241 W$

(b) 10624 W

The maximum power is provided during the phase of acceleration, because during this phase the force applied is maximum. The acceleration of the car can be found with the equation

$v=u+at$

where

v = 2.20 m/s is the final velocity

a is the acceleration

u = 0 is the initial velocity

t = 12.0 s is the time

Solving for a,

$a=\frac{v-u}{t}=\frac{2.20-0}{12.0}=0.183 m/s^2$

So now the equation of the forces along the direction parallel to the incline is

$F - mg sin \theta = ma$

And solving for F, we find the maximum force applied by the motor:

$F=ma+mgsin \theta =(950)(0.183)+(950)(9.8)(sin 30^{\circ})=4829 N$

The maximum power will be applied when the velocity is maximum, v = 2.20 m/s, and so it is:

$P=Fv=(4829)(2.20)=10624 W$

(c) $5.82\cdot 10^6 J$

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The change in potential energy of the car is:

$\Delta U = mg \Delta h$

where

m = 950 kg is the mass

$g=9.8 m/s^2$ is the acceleration of gravity

$\Delta h$ is the change in height, which is

$\Delta h = L sin 30^{\circ}$

where L = 1250 m is the total distance covered.

Substituting, we find the energy transferred:

$\Delta U = mg L sin \theta = (950)(9.8)(1250)(sin 30^{\circ})=5.82\cdot 10^6 J$

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3 years ago

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MaRussiya [10]

The coefficients in order are 2, 1, 1

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A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.

In other words, the mass and the charge are balanced on both sides of the reaction.

According to the given situation,

To balance the the chemical equation,

Step 1 - Add a 2 on the Na2HPO4:

2(Na₂HPO₄) ⇒ Na4P₂O₇ + H₂O

Step 2 -Next take count of each element on both sides to see if the 2 is balanced or not:

On the left there are 4 Na, 2 H, 2 P, and 8 O

On the right there are 4 Na, 2 H, 2 P, and 8 O

Step 3 - Now we will divide by 2

i.e. 2 NA.H. P

The coefficient of Na is 2 , Coefficient of H is 1 and Coefficient of P is 1

Therefore,

The coefficients in order are 2, 1, 1.

Learn more about balanced chemical equation here:

brainly.com/question/15052184

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8 0

2 years ago