Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
Net pulling force on the chain is due to weight of the part of the chain which is over hanging
So we know that mass of overhanging part of chain is given as
now net pulling force on the chain is given as
now acceleration is given as
Part b)
Tension force in the part of the chain is given as
Part c)
velocity of the last link of the chain is given as
now integrate both sides
7 and a half days should be the answer
If a potassium atom loses one electron than it becomes a +1 charge, because the electrons are negative and the nucleus is positive (the positive comes from the protons). The protons and electrons balance out so it has a neutral charge, but if the atom loses an electrons it has a positive charge, but if the atom gains an electron than it becomes negative. the charge (+/- and the number) of the atom depends on how many electron the atom gains/loses.
the answer is (D.) +1
I hope this helps.
Intially, we have:
Pressure P1 = 400KPa
Temperature T1= 110Kelvin
When,
Temperature T2= 235 Kelvin
Pressure P2= ?
We have gas equation:
PV= nRT
P/T= nR/V
Considering nR/T as constant, we have:
P1/T1 = P2/T2
400/110= P2/235
P2= 854.5 KPa
So the new temperature will be 854.5 KPa
Answer:
τ = 1679.68Nm
Explanation:
In order to calculate the required torque you first take into account the following formula:
(1)
τ: torque
I: moment of inertia of the merry-go-round
α: angular acceleration
Next, you use the following formulas for the calculation of the angular acceleration and the moment of inertia:
(2)
(3) (it is considered that the merry-go-round is a disk)
w: final angular speed = 3.1 rad/s
wo: initial angular speed = 0 rad/s
M: mass of the merry-go-round = 432 kg
R: radius of the merry-go-round = 2.3m
You solve the equation (2) for α. Furthermore you calculate the moment of inertia:
Finally, you replace the values of the moment of inertia and angular acceleration in the equation (1):
The required torque is 1679.68Nm