Question

How many ml are in 1.25 l of a intravenous solution of 0.9% sodium chloride?

Answer 1

Mass % of NaCl = 0.9 % (m/v)

Density of 0.9 % NaCl is about 1.0 g/mL

Volume of NaCl in mL :

$1.25 L solution * \frac{1000 mL}{1 L} * \frac{0.9 g NaCl}{100 mL solution}*\frac{1 mL}{1.0 g NaCl}$

= 11.25 mL NaCl